Nodal Analysis - Engineering Electrical Circuits - Lecture Slides, Slides of Electrical Circuit Analysis

Download Nodal Analysis - Engineering Electrical Circuits - Lecture Slides and more Slides Electrical Circuit Analysis in PDF only on Docsity! Chp3 Nodal Analysis & MATLAB Docsity.com os FeRoe | Hvar 4= alone, | # gL Hayward, CA 94545 eMail: bmayer@ chabotcallege.ed| pe CkKT ~ FIND POWER Fok [OHA T-seCc KOOPS — NOTICE —- ONE L-SEC = CK COIS FRAY OWE LovP — TWO V~SROS =D CAN COV Ene Al TG NODES PMS & CHOOSE NODAK AAlALY3/S Z80 CHOSE GNO AS PHNOST Cease MoBigecom Last of The Hand-Soln Of 4 BOV, — 2SV2 — ¥V3 - /ONy = - ZOOV @ Now iv” AN =B MATRIK FORM Pi = Ew] [ev ww ee ft UE oP | Ve Pd eH | GeV “4 7-2 || Ysi | OV | 2e -25 -¢ “0 | Ye p eee ~ v B NoTé! A =>? unirTeess (BY 4e0 MucT) B= Voom SOLVE BY MATLAB Litter ALGEBRA — COLLD ALSO Sos. — 806 STITT) OV — GRUSSIANM CECLHUNM ATION ® Docsity.com The .m Script File % ENGR43_Chp3_Nodal_Analysis_MATLAB_Tutorial_0602.m % Bruce Mayer, PE % ENGR43 * 05Feb05 % % The Coeffiecent Matrix A (unitless) A = [1 0 0 0; 0 0 -1 1; -4 7 -2 0; 30 -25 -4 -10] % % The Constraint Vector B B = [40; 60; 0; -200] % in Volts % % Solve by MATLAB "Back Division" V = A\B; disp('The Solution Vector, [V1; V2; V3; V4] in Volts = ') disp(V) % % Power to I-Src is V4*10mA disp('Power Supplied by 10 mA current source in mW =') disp(V(4)*10) Docsity.com The Solution • From ENGR43_Chp3_Nodal_Analysis_MATLAB_Tutorial_0602.m A = 1 0 0 0 0 0 -1 1 -4 7 -2 0 30 -25 -4 -10 B = 40 60 0 -200 The Solution Vector, [V1; V2; V3; V4] in Volts = 40.0000 25.9459 10.8108 70.8108 Power Supplied by 10 mA current source in mW = 708.1081 Docsity.com