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Organic Chem I Exam 3: Naming, Radical Formation, & Reactions, Exams of Organic Chemistry

The third exam for the organic chemistry i course (chemistry 331) focusing on topics such as naming compounds according to iupac rules, radical formation, and reactions including hydroboration, oxidation, and halogenation. Students are required to calculate percentages of products based on probability and reactivity, and complete transformations while considering stereochemistry.

Typology: Exams

Pre 2010

Uploaded on 07/23/2009

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Download Organic Chem I Exam 3: Naming, Radical Formation, & Reactions and more Exams Organic Chemistry in PDF only on Docsity! Chemistry 331 Organic Chemistry I Exam 3 Butadiene ψ4 ψ3 ψ2 ψ1 Points: Q1:10; Q2:20; Q3:20; Q4:20; Q5:10; Q6: 10; Q7:10; Q8: 10 TOTAL: 110 Name ________________________________________________________________ (please print) CH 331, Exam 3 – Page 1 1. Give the IUPAC name for each of the following compounds (10 points): Hint: DON’T FORGET E/Z , cis-trans NOTATION. a) CH3 CH3 (1R,6S)-1,6-dimethylbicyclo[4.1.0]heptane b) Cl CH 1-chloro-5-ethynylbicyclo[4.2.0]octane c) CH CH3 CH3 CH3 (4E,8E)-5,7-dimethyldeca-4,8-dien-1-yne d) CH2 CH2 7,8-divinylcycloocta-1,3,5-triene e) Br Br 6,7-dibromospiro[4.5]decane CH 331, Exam 3 – Page 4 3. Complete the following transformations. Be sure to consider stereochemistry where appropriate. Indicate the type of reaction. For Questions b,c,d name the compound. (4 points each) a) CH CH3 O H2O, H + b) CH3 CH H CH3 O 1. Hydroboration, B2H6 2. Oxidation, H2O2, OH - c) CH2 CH3 CH3 3 Br2, CH2Cl2, ionic BrBr Br d) CH3 CH3 CH3 NBS, CH2Cl2 CH3CH3 BrBr CH3 CH3 CH3 e) CH3 CH3 CH3 CH3 CH3 H H CH3 CH3 CH3 CH3 CH3 Na/NH3 CH 331, Exam 3 – Page 5 4. Which Diene and which Dieneophile could be used to prepare the following compounds. (20 points) a) CH3 N CH3 + CH2 N b) F F F F F F FF c) O O O O CH3 CH3 O O CH3 O O CH3 H CH3 CH3 OH O CH3 CH3 d) CH 331, Exam 3 – Page 6 5. Which of the following materials are aromatic? Briefly explain why (use Hückel’s rule.). (10 points) CH + CH + O O N N N N H CH + CH + A: Not aromatic : 4 pi-electrons B: Aromatic: 18 Pi electrons C: Not aromatic: not all Pi electrons part of a ring system D: Aromatic: 10 Pi electrons ( two from lone pair at nitrogen E: Aromatic: 2Pi electrons. So B,D,E follow Hueckel-rule: (4n+2), for n=0 (E), n=2(D), n=4(B)
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