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Partial Fractions Cheat Sheet, Cheat Sheet of Mathematics

partial fractions decomposition technique and other formulas with examples

Typology: Cheat Sheet

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Uploaded on 04/27/2021

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Download Partial Fractions Cheat Sheet and more Cheat Sheet Mathematics in PDF only on Docsity! 1 Haroldโ€™s Partial Fractions Cheat Sheet April 2016 Partial Fractions (http://en.wikipedia.org/wiki/Partial_fraction_deco mposition) Condition ๐‘“(๐‘ฅ) = ๐‘ƒ(๐‘ฅ) ๐‘„(๐‘ฅ) = ๐‘Ž๐‘ฅ๐‘› + โ‹ฏ + ๐‘ ๐‘๐‘ฅ๐‘š + โ‹ฏ + ๐‘‘ where ๐‘ƒ(๐‘ฅ) ๐‘Ž๐‘›๐‘‘ ๐‘„(๐‘ฅ) are polynomials Preparation Case 1: ๐‘› โ‰ฅ ๐‘š, Peform long division first Case 2: ๐‘› < ๐‘š, Proceed to the cases below Case I: Simple linear (๐Ÿ๐’”๐’• degree) ๐ด (๐‘Ž๐‘ฅ + ๐‘) Case II: Multiple degree linear (๐Ÿ๐’”๐’• degree) ๐ด (๐‘Ž๐‘ฅ + ๐‘) + ๐ต (๐‘Ž๐‘ฅ + ๐‘)2 + ๐ถ (๐‘Ž๐‘ฅ + ๐‘)3 Case III: Simple quadratic (๐Ÿ๐’๐’… degree) ๐ด๐‘ฅ + ๐ต (๐‘Ž๐‘ฅ2 + ๐‘๐‘ฅ + ๐‘) Case IV: Multiple degree quadratic (๐Ÿ๐’๐’… degree) ๐ด๐‘ฅ + ๐ต (๐‘Ž๐‘ฅ2 + ๐‘๐‘ฅ + ๐‘) + ๐ถ๐‘ฅ + ๐ท (๐‘Ž๐‘ฅ2 + ๐‘๐‘ฅ + ๐‘)2 + ๐ธ๐‘ฅ + ๐น (๐‘Ž๐‘ฅ2 + ๐‘๐‘ฅ + ๐‘)3 Example Expansion ๐‘ƒ(๐‘ฅ) (๐‘Ž๐‘ฅ + ๐‘)(๐‘๐‘ฅ + ๐‘‘)2(๐‘’๐‘ฅ2 + ๐‘“๐‘ฅ + ๐‘”) = ๐ด (๐‘Ž๐‘ฅ + ๐‘) + ๐ต (๐‘๐‘ฅ + ๐‘‘) + ๐ถ (๐‘๐‘ฅ + ๐‘‘)2 + ๐ท๐‘ฅ + ๐ธ (๐‘’๐‘ฅ2 + ๐‘“๐‘ฅ + ๐‘”) Typical Solution for Cases I & II โˆซ ๐‘Ž ๐‘ฅ + ๐‘ ๐‘‘๐‘ฅ = ๐‘Ž ln|๐‘ฅ + ๐‘| + ๐ถ Typical Solution for Cases III & IV โˆซ ๐‘Ž ๐‘ฅ2 + ๐‘2 ๐‘‘๐‘ฅ = ๐‘Ž ๐‘ ๐‘ก๐‘Ž๐‘›โˆ’1 ( ๐‘ฅ ๐‘ ) + ๐ถ Steps to Solve Example 1. Write down problem โˆซ 5๐‘ฅ + 1 2๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 1 ๐‘‘๐‘ฅ 2. Check if long division is needed Not needed since degree of numerator (top) is less than degree of denominator (bottom) 3. Factor denominator of function 5๐‘ฅ + 1 (2๐‘ฅ + 1)(๐‘ฅ โˆ’ 1) 4. Expand function with A, B, Cs 5๐‘ฅ + 1 (2๐‘ฅ + 1)(๐‘ฅ โˆ’ 1) = ๐ด (2๐‘ฅ + 1) + ๐ต (๐‘ฅ โˆ’ 1) 5. Get a common denominator = ๐ด(๐‘ฅ โˆ’ 1) (2๐‘ฅ + 1)(๐‘ฅ โˆ’ 1) + ๐ต(2๐‘ฅ + 1) (2๐‘ฅ + 1)(๐‘ฅ โˆ’ 1) 6. Focus on numerator 5๐‘ฅ + 1 = ๐ด(๐‘ฅ โˆ’ 1) + ๐ต(2๐‘ฅ + 1) 7. Expand/distribute/FOIL 5๐‘ฅ + 1 = ๐ด๐‘ฅ โˆ’ ๐ด + 2๐ต๐‘ฅ + ๐ต
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