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Past Exam 1 with Solutions - Digital VLSI Design Systems | ECEN 5263, Exams of Electrical and Electronics Engineering

Material Type: Exam; Professor: Johnson; Class: VLSI DIGITAL SYS DES; Subject: Electrical and Computer Engineering ; University: Oklahoma State University - Stillwater; Term: Spring 2001;

Typology: Exams

2010/2011

Uploaded on 07/17/2011

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Download Past Exam 1 with Solutions - Digital VLSI Design Systems | ECEN 5263 and more Exams Electrical and Electronics Engineering in PDF only on Docsity! ECEN 5263 Spring 2001 Exam 1 WRITE YOUR NAME HERE SOLUTIONS All questions must be answered on test paper! Open Book, Open Notes 1. A certain process has the following parameters. toy = 0.015pm ‘ox e,, = 3.5x10 UF /m fs; = 14x10 °F /m b, = 0.08m2/(V-sec) p= 0.04m?/(V-sec) Vy = 0.6V Vip = -0.6V = 1.0x10° m/sec y=02v"2 o = 0.8V Answer the following questions for an nMOSFET with W=2.0p.m, L=0.5ym and drain punch through parameter, 2=0.1V74, a. What is 8? = um 2%. (W = fan 222 M fox Ct %) } = (0B) (4:Sxib ) 1SX10" >.( = veri | 46 X10 veri | ve (6.01 8K00) 6-01 5x10 (i ' 3) b. What is the critical voltage for velocity saturation, V,? 5 - Veo Cmax yy = 19%)? (ors xiom®) Ain 0 0D ECEN 5263 Spring 2601 Exam 1 February 19, 2001 page 1 of 4 4 c. What is Vp when Vsp = 2.3V assuming that the original Vy above was for Vp = OV? Vr = Vet DMV Wel 42g - 120 >? 2 Ob+ o2(Jfaslt2(o0) ~—0 elo) ) = 016+ oi2C1-g3uB — 1 2644) Vp = or THia® v d. What is Vince when Vgs=3.3V? Use the results of previous parts when appropriate. Vosat = Vas-V1— ({ c+ (ast )*Ve ) ~ 3:3 ~(ormHd ) (Go, 025) "4 (2.85002) ~ 0625) = 2155$02 — | 2.6333-0.625] Vosot = o1suatv] . e, What is Ip when Vp = 0.5V? Use the results of previous parts when appropriate. Vosat = 0 yA *7 Since Vos < Vpsat Vps = 045 and Yas? VT =p LINEAR REGION Ap = BL CVas-Vr Wos -Vod/2 11+ A¥ps) = (raexie DL (56002) (015) — ()" J(1+ onNC0r5)) a lp = 4-034y x07 A f. What is Ip when Vps =3.3V? Use the results of previous parts when appropriate. Vos 77 Vosat Z saturation Vas 7VT Vas-Vt = 2:85B027 yo nop ye fe a GAT Ip Ve = 01625 Tp = pve WME + (Veg-ve y= Ve) = (4yexto C06 259 T2:6 333 19.620) To = G.Zhaip a ECEN 5263 Spring 2001 Exam 1 February 19, 2001 page 2 of 4
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