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Worksheet: Calculating Empirical & Molecular Formulas
1. The empirical formula for the compound having the formula H2C,0, is:
[A] CoH [Cc] COH [D]}C,0.H, โ [E] COH2
2. Calculate the empirical formula of a compound that is 85.6% C and 14.4% H (by mass). H 4
a ยขC 85.6 ayn et = 14,25_
COACH: ) [BCH IC]CHs DICH. EH โTeor gel hol oS 2
3. A compound is analyzed and found to contain 12.1% carbon, 16.2% oxygen, and 71.7% chlorine (by
mass). Calculate the empirical formula of this compound. 2 fa he EE: ao)
(ICO, โ[e]Coaci_ |DJGoCK = feJCoc! ype HS
1600
4. A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen (by mass).
Calculate the empirical formula. Be '
Catt Pe S33.
โ20! F, i = 3.3
1A) C220 | CH.D)IC] CHO [D] C,Ho2 [E] C3HeO3 ne โ3 46 pa
ae *
5. A compound contains 25.94% N and 74.06% O (by mass). What is the empirical forfhil la?
Z25:949N_ 1,8.
Tb 7 โ wef = | x2 = 2 [Was |
T40lg O _
1u.00 = H.b3 2 265 x2 > 5
6. Determine the empirical formula ofa compound containing 54.2% F and
45.8% S (by mass). Sa, 26h SS 35 aE : โ9 " 2
3. . m =7i
VAS
19.00 g/mol ~
Nsepgs |e eS
32.079/mo? wen a
7. Acompound has 40.68% carbon, 5.12% hydrogen, and 54.20% oxygen (by mass)
Calculate its empirical formula.
: 209 O
HOW 35S = 3.387 Sil2gH _ 5.004 St26q = 3.397
Os 120O'4lonat S55 VON mal SA MOOG 5-397
=ly2<2 = 14 x2= 3 = 14222
8. A7.33-g sample of lanthanum, La, combines with oxygen to give 10.29 g of the oxide. Calculate the
empirical formula of this oxide. 10.296 โ 2.334 โ 246g e&
7.33gl4 =,0527 29420
1S Bil g/mol 39887 โโ pA = 1850 23.5 4927
21a nat O527
9. Calculate the molecular formula of a compound with the empirical formula CHO โ_ and a molar mass
of 150 g/mol 30 1s0 430-5
TA] CsH.O3 [C] CoHs02 [D] CeHeO, โ[E] CoH 206