Physics I Final Exam: Formula Sheet for Translational and Rotational Motion, High school final essays of Physics

Download Physics I Final Exam: Formula Sheet for Translational and Rotational Motion and more High school final essays Physics in PDF only on Docsity! Physics I. Final Exam Formula Sheet Translational Motion x= x2 – x1 (displacement) vaverage=x/t aaverage=v/t Given x(t) v(t) = dx/dt a(t) = dv/dt = d2x/dt2 Kinematic eq-ns with const. acc.: v(t) = v0x+at x(t) = x0+ v0xt +(1/2) at2 v2 = v0x 2 + 2a(x – x0) Newton 2nd law F ma F dP dt Frictional Forces: Fs ≤ µsFN Fk = µkFN For springs: F = -kx U(x) = (1/2)kx2 Linear Momentum and Impulse  p  m  v tFdtFJ av   For elastic collision:  pA   pB   p 'A  p 'B 1 2 mAvA 2  1 2 mBvB 2  1 2 mAv 'A 2 1 2 mBv 'B 2 For 1-D elastic head-on collisions: )''( BABA vvvv  Work and Kinetic Energy W = Fscosθ W F ∙ ds Ktrans = (1/2)mv2 ; Krot = (1/2)I2 Ktot = (1/2)ICM2+ (1/2)MvCM 2 Work-Kinetic Energy principle Wnet = K With non-conservative forces: K + U = WNC Centripetal acceleration: aR = v2/R; aR = 2R Rotational Motion = 2 – 1  = ddt  = ddt Given θ(t) (t) = d θ/dt α(t) = d/dt = d2θ/dt2 Rotat. kinematic eq-ns with const. angular acceleration (t) = 0+t (t) =0+0t +(1/2)t 2 20 2+ 2 (–0) Rotat. Newton 2nd law τ Iα τ dL dt Angular Momentum prL   ;   IL  I = miRi2 Torque Fr   ; = r F sin Potential Energy F(x) = - dU(x)/dx For gravity on earth's surface: Fg = mg U(y) = mgy For gravity in general: Fg = - GmME/R2 U(r) = - GmME/R g = 9.8 m/s2 ; G = 6.67 x 10-11 N.m2/kg2 Total mechanical energy: Etot = K + U Power Pavg = W/t; P = dW/dt; Equations connect. trans./rotat. motion vtan = R atan = R  x x FdxxUxUU 0 )()( 00 P   F   v