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Point Charges - Introductory Physics - Solved Paper, Exams of Physics

These are the notes of Solved Paper of Introductory Physics and its key important points are: Point Charges, Potential Energy, Electric Potential, Initial Direction, Magnitude of Magnetic, Moving Particle, Circular Path, Full Revolution

Typology: Exams

2012/2013

Uploaded on 02/12/2013

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Download Point Charges - Introductory Physics - Solved Paper and more Exams Physics in PDF only on Docsity! I Udrersiry ol Cdifomi. 't Berk ley Departne of?hysics Physi$ 88, Frll 2008 S.ction 2 Midlern I ocrobei 7, ?003 You pill be given I l0 nidutes lo work this enn. No bsks are alloNed. but you nay use a h.ndwritten fomulae sheer no Isrg€r than one side ofo 8 %' by I l" sh€et ofpape!, Your deeriprio. of fie physics iNolved in a prcblem is wonh sisnificohtly more thm ey nuncrical osNer, Sbow all @ , dnd bke pdliculft caE ro expl.in what you d€ doing. Please rse lhe sJmbols descnM ih rhe problems, t€ll us why you'E wriling any n€w equlions, and ldb.l any dawings lhd you make. writc you o.swers disdy on the em, ahd ifyou have to use the bs( ofa sheet nake suF to put ! not on rhe 6ont, Do not ue a blud book or scarch laper. DISCUSSION SECTION NUMBER: I (25) 2 (2t 3 (2t o00) IA ,Pe J>eW ne'e SIDNUMBER: DISCUSSION SECIION DATEIIME: i Fomulie: (You may hot n.cd ali of lhesel) F=P+, E=k+i v=kgl i k--L i-F\E p=qd r 4ftn ,"a. ,"!r 'a 0.. t . r^u. tv N !u.^ , ' : r aL-qn.3 v >v :>! 11.a , ra! in ,' : 4 L " ' : , ' l o ct c- ' "A , -z^ ! c c*^ ab | . t . t - Q' d "h(b4 b t z z . t=!! r=L r=u=tn=! xt=!., ' dIRR2 n-=fr, r-=, I q,B--" i , - , t , i i , t , -R 4n l t -4 { i 'd . p" t " a Lh a=P"Nl' 2nr a, - lB t tA=DA qt a-ent - - - t " - ' ! - - t " L=!9r L=u, 'al v=14! u=!y ' I "d t2 u, u,, , d| i \t r )=L-; ; th - lvnb vrt - ) lh. t = -L = 9/to ' N . n) /c ' r . =9x10 'C ' /N m' charyeonane lec ton=-1 .6 ! l0 r ' c D Problen2 - Big Crpicltor lro flal sqlare meklthlcs rhdr ato ca.h l0D on ! sidc arc splm.cd by & disnncc D = lxi or'n'lie lcli nhie h$ a bral ch.rg.ofQr = 6C. shilc $c riehr pl chchar$dupro QR = +6C AwiEconncrs id lert plak ro a rcisro. \ irh rsi$.aR=2xltro.but$erighlP|a!cisiniiia||Idisconnectcd Fom the resinor du. ro .n dp.n $r itch. a) What is thc.lcclk poreniialdiffe.ence ber!-ccn rhe ptaresl ts a.t /1 ' r l I thepotential highcron lhc lcli or dghr pldrc? b) Whatkthesrrergrhrnddirecrionorrfu c clrlouctdbc$een c) lf!smallch.rg.d pi.ce ofplanic wirh nr$ m =:xt0rkg n re[ased ilom ruial rhe len plalc. rnd n a.cclcEr.s ontil it schieres a ffral spccd of 20 nts al rhe riahr phG. th.n whar is lhe sign dd rognitudc ol tlrc chffgc? Yoo nat ncglcct gn\ irJ . d) r''?dd€r aicr.losing the s* irch. \ har is fic.uftnr thftugh ih. Bsisro..l .) How lons 0n&rhe ssitch is closed *ill rhc.urcnr drcp ro l/e'- 0 05.ra's ini'i.!vlLu:?i]; a) Ane,r. A . (D\N'"^)=tba\z \ i..,r",ri r"" | ,,t\t l /,.k .,,n.i+at t i .&? /i. + :5 i u)t.El,e = i- +;:.r",:;:;l'""6 cans olf re,11: F?r,it, .-. t 'ti +rti ') trat- PF pF" "t \)2", q(V; -v+ ) (/,,, , <ne a"'t ) ,l) ;a*ahakQ q{.kr s*i+cL ;t r(*'a[., ca(a'))1r rnll lar 6qn2 "l\ Q.= tc o( cLary4 a^ e^.L l(a te / t. U)t y 4cvatt | <;;SJE} ,r .fl,+. ran-z 4t 414 Va\+7/jz acrot! . 'etAC .r ' . Ltfvg r,.nl. I / ,)4r .(, f2.{: Y,,,$ll 't L"* lo" tt"t+,vt g ,"*a."".t' a? Fg -,J. _r",?=oW2," ,,y=+A ({ L ctr.ait 1rt ^ -6 tNto - = 3,uF 3 tro6 r) e =!. e -trz. ,3 e -€ €r= -> t = 3 Kc - \ t l6t l o . ,* t= Rc =(2rro"st)( - / - + Irt:= o) e '/E r' €*'7' ,1 {L,s +-I"e-, -I- Rc a f rty=T. , . <,2+ :tr.] PoblemS Cha€edParticle inMagnetic Field At t = 0. an oxotic paniclc wnh charec Q = +lC and n.s m = lB is 'novingro the ght with d initirlspeed olv = lonts. There h r unifom magnelic field of 2 l inlo d,e page. You'nay neglect gavily a) What isthe innialdnection ard mlenitude ofthe masnetic 1orce on rhe noving paniclc? b) What k the radius of$ecirtularpnh f.llo*ed by thc padicle? c) How much Nork is done on the panicle by lhe nagnetic field during ./. ofarevolution about its ciftular path? d) How lone will i1tlke for the panicle to make one fullrevolution? e) Ila sscond padiclc with charge Q = -3c is lEvelin8 staighl out of thc pas., vhat is lhc forc. on dEr padiclc due to rhe unjfom nagneic neld? j ,7 : t ' . - lat r_-.,o.8 .t .a., - ' .,.t" ., .a: :.,, X I X X? r r l xL i i , t . . )4 ts r s r l p4"t_!_9]:3 t_ 20N { .F: I /?. -5 -., w_ = fir ,) +"rl -T _ 1 , /v I 7; ' ienl f";rt21 :p) na vorE ,'n ^^artt t c t/1,.yt B 1 o,+1"7o^al t) a \ - , B lge: ," di tL= A 1f lo jztlt = d ,: r"itdt e).c.T-4-.-B.-.3.E" a
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