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Let (X, T) be a topological space and let A < X, then the inter-
section of all closed set which are superset of A is called the
closure of A and is denoted by A.
Example : Let X = {a, b, c, d, e}
T = {, X, {a}, fa, b}, {a, c, d}, {a, b, e}, {a, b, c, d}}
Then find closure of {c, e}
Solution : The closed subset of X are
, X, {b, c, d, e}, {c, d, e}, {b, e}, {c, d}, {e} then
A= {c, e}={b, 6, d,e} 0 fc, d,e} aX
= {c, d, e} 5
Let (X, T) be topological space and let A, B < X, then
1. Ais said to be dense in Biff BCA.
2. Ais everywhere dense in X iff A = X.
3. Ais no-where dense in X iff (A)° = 6.
4. Ais dense in itself iff A < D(A).
Let X = {a, b, c, d, e} and =
T = {, X, {a}, {b, c}, fa, b, c}} |
then check the set A = {a, d} is dense in
B = {a, b, c, d}.
Solution : Closed set are
, X, {b, c, d, e}, {a, d, e}, {d, e}
So, A= {a, d, e}
but BcA
=> Ais not dense in B.
Let X = (a, b, c} and T = (6. X. {b), {a,b},
then closure of A= {b, c}
Q {b. ¢} g {a, b. c}
@ @) Q «©
Let R be the set of all real numbers. Let U be the family of
subsets of R consisting of # and all non-empty subset G of R
having the property that to each x € G, 4 an open interval |,
such that x < |, < G, then U is topology on R, called the usual
topology i.e. U = {(a, b), (c, d), (a, b) u (ec, d), «0... }
OR
Let U consist of » and all those subset G of R which are
neighbourhood of each x € G. The topological space (R, U) is
called usual topological space.
_
—
o-
ow
iG)
Q.
LOWER LIMIT TOPOLOGY FORR
Let R be the set of all real numbers. Let S be the family of all
subset of R consisting of > and all non-empty subset G of
having the property that to each x € G J a right half open interval
[a, b[ s.t. x € [a, b) c G, then S is called lower limit topology
for R. - ia ,
L T T
a x b
The topological space (R, S) is called lower limit topological
space.
Note : (i) Every open interval containinS. 9 ~——*+3-+—+—
(ii) Interval of type [a, b) contained in S. —1 ae
(iii) (a, b] ¢ S because b « (a, b]
but # any right half open interval [b, p) > ___
s.t.b efb,p) < (a, b]
Let R be the set of all real numbers. Let H be the family of all
subset of R consisting of and all non-empty subset G of
having the property that to each x <« G 4 a left half open interval
(a, b] s.t. x € (a, b] c G, then H is called upper limit topology
for R.
The topological space (R, H) is called upper limit topological
space.
GcR
—_
ro)
|
T
a x b
Show that the every closed interval [a, b] is
closed in the usual topology for R.
Solution : G = [a, b]’ = (-», a) U (b, ~)
G is neighbourhood of each point x <« G.
So, (-%, a)U (b, 0) e U
=> (-», a) U(b, ») is open set
=> [a, b] is U-closed set.