Principle of Superposition - General Physics - Solved Past Paper, Exams of Physics

Download Principle of Superposition - General Physics - Solved Past Paper and more Exams Physics in PDF only on Docsity! 3. (20 pts) Two charges are located 10 cm apart, as shown below, where q1 = 12 nC and q2 = −8 nC. 10 cm 10 cm 10 cm q1 q2 a) Compute the electric potential at the indicated point located 10 cm from both charges. V1 = ( 8.99 × 109 ) ( 12 × 10−9 ) 0.1 = 1078.8 V V2 = ( 8.99 × 109 ) ( −8 × 10−9 ) 0.1 = −719.2 V Then, since electric potential obeys the principle of superposition, V = V1 + V2 = 1078.8− 719.2 = 359.6 V b) How much energy would be required to place an electron (qe = −1.6×10 −19 C) at the indicated point? ∆U = q∆V = ( −1.6 × 10−19 ) (359.6) = −5.75× 10−17 J Since this result is negative, the electric potential of the electron decreases as it moves from infinity to the indicated point. In order to make the electron stop at the desired point, we would have to actually restrain the electron rather than push it into place.