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Principles of Mathematical Inductions in Analysis I | MATH 554, Study notes of Mathematics

Material Type: Notes; Professor: Sharpley; Class: ANALYSIS I; Subject: Mathematics; University: University of South Carolina - Columbia; Term: Fall 2008;

Typology: Study notes

Pre 2010

Uploaded on 10/01/2009

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Download Principles of Mathematical Inductions in Analysis I | MATH 554 and more Study notes Mathematics in PDF only on Docsity! Math 554/703 I - Fall 08 Lecture Note Set # 2 Please read Chapter 2 of Rudin which deals with the concepts of countability (pages 24โ€“30) and the metric space topology (pages 30-36). Some portions are outlined again here for convenience. Defn. a) Two sets are said to have the same cardinality and are called equivalent if there exists a 1-1, onto mapping from one to the other. This determines an equivalence relation. b) Consider the set Jn := {1, 2, . . . , n}. A set A which is equivalent to Jn, for some n, is called finite with cardinality n. This is the number of elements of A. c) A set is called infinite if it is not finite. d) A is called countable if it has the same cardinality as the natural numbers IN . e) A is said to be at most countable if it is countable or finite. We showed in class that the integers and the rationals were countable, but that the irrationals were not. (We only indicated the proof of the last statement since it needed some elementary properties of sequences which we cover in Lecture Set # 4.) Moreover, we showed ... Theorem. The union of at most a countable number of at most countable sets is at most countable. (recall to use a diagonal argument) Theorem. Every infinite subset of a countable set is countable. Defn. A sequence in a set A is a mapping f from the natural numbers to A, which may be written as {a1, a2, a3, . . .} where aj := f(j), j โˆˆ IN . We recall the concept of mathematical induction which is applied to a sequence of statements. Theorem. (Principle of Mathematical Induction.) Suppose that a statement p(n) is defined for each natural number n. If 1. p(1) is true 2. ((p(n) true) =โ‡’ (p(n+1) true)) is a true statement for each n โˆˆ IN, then p(n) is a true statement for each natural number n. Proof. Suppose to the contrary that the set B := {n โˆˆ IN | p(n) false} is not empty. Notice that 1 6โˆˆ B. Let N be the smallest element of B (possible since you can take a minimum of a finite set of integers), then set n := N โˆ’ 1. Observe by assumption (1) that n โˆˆ IN , and by the definition of B that p(n) is true. By assumption (2), it follows that p(n+1) is true. But n + 1 = N . Contradiction. Hence B must be empty. 2
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