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Statistical Analysis of Weight Gain Side Effect of Depakote in 600 Patients, Study notes of Statistics

A statistical analysis of the number of patients experiencing weight gain as a side effect of depakote medication in clinical trials and extended studies. It calculates the mean, standard deviation, and probabilities of observing a certain number of patients with weight gain using the binomial distribution and normal approximation. The analysis also discusses the range rule of thumb and the rare event rule.

Typology: Study notes

Pre 2010

Uploaded on 03/11/2009

koofers-user-8pq
koofers-user-8pq 🇺🇸

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Download Statistical Analysis of Weight Gain Side Effect of Depakote in 600 Patients and more Study notes Statistics in PDF only on Docsity! CHAPTER 6 12) Depakote is a medication whose purpose is to reduce the pain associated with migraine headaches. In clinical trials and extended studies of Depakote, 2% of the patients in the study experienced weight gain as a side effect. a) Compute the mean and standard deviation of the random variable X, the number of patients experiencing weight gain in 600 trials of the probability experiment. Population: migraine headaches sufferers who use Depakote Success attribute: Experience weight gain as a side effect n = 600, p = .02 * 600*.02 12 * * 600*.02*.98 11.76 ~ 3.4 n p n p q         b) Would it be unusual to observe 16 or more patients who experience weight gain in a random sample of 600 patients who take the medication? Explain why for each of the following. (i) According to the range rule of thumb [12 – 2*3.4, 12 + 2*3.4] = [5.2, 18.8] It’s usual to observe anywhere from 6 to 18 people experiencing weight gain in groups of 600, so 16 is usual (ii) To use the probability rule, calculate P(x ≥ 16)  Use methods of chapter 5 to calculate the probability. P(x ≥16) = 1 – binomcdf(600, .02, 15) = .1534 (exact) Since this probability is higher than 0.05, according to the probability rule, it’s common to observe 16 people experiencing weight gain in groups of 600  Verify that the normal distribution is appropriate to estimate this probability. Both, n*p and n*q must be greater than or equal to 5 Since n*p = 600*0.02 = 12 and n*q = 600*.98 = 588 Then the normal distribution is appropriate to estimate this probability  Estimate the probability by using the normal distribution. Use the continuity correction factor. (Note: for large n, the continuity correction factor may not be necessary) Show steps, and then check with calculator feature. Remember to answer the question to the problem. USE CALCULATOR ONLY for the normal approximation Normalcdf(15.5,10^9, 12, 11.76 ) = 0.1537 (approximation) Since this probability is higher than 0.05, according to the probability rule, it’s common to observe 16 people experiencing weight gain in groups of 600 Page 20
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