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EE422G Homework #1 Solutions: Linear Systems, Fourier Transform, and Laplace Transform, Assignments of Signals and Systems

Solutions to various problems related to linear systems, fourier transform, and laplace transform. It includes the determination of linearity for given systems, definitions and properties of fourier transform and fourier series, finding the laplace transform and region of convergence for specific functions, and using matlab to plot a given function. Additionally, it covers finding the roots of the product of two polynomials.

Typology: Assignments

Pre 2010

Uploaded on 10/01/2009

koofers-user-04i
koofers-user-04i 🇺🇸

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Download EE422G Homework #1 Solutions: Linear Systems, Fourier Transform, and Laplace Transform and more Assignments Signals and Systems in PDF only on Docsity! EE422G Homework #1 Solution 1. (4 pts) Determine which of the following systems are linear. Explain your answer: (a) dy(t)dt + 3y(t) = 4x(t) Solution: Yes, it is linear. The reason is that given two pairs of input-output signals x1(t), y1(t) and x2(t), y2(t) that satisfy the differential equation, it is clear that ax1(t)+bx2(t) and ay1(t)+by2(t) are also a solution to the differential equation as shown below: d dt (ay1(t) + by2(t)) + 3(ay1(t) + by2(t)) = a [ d dt y1(t) + 3y1(t) ] + a [ d dt y1(t) + 3y1(t) ] = ax1(t) + bx + 2(t) (b) The impulse response: h(t) = δ(t + 2) Solution: Since the system has an impulse response, it is definitely linear. (c) y(t) = x2(t) + 2dx(t)dt Solution: It is non-linear due to the second degree term – when using a similar test as part a), you will notice that the second degree term creates a cross term x1(t)x2(t) that is not present in the differential equation. (d) Solution: The system is non-linear. This is a little bit tricky. As we know, for all lin- ear systems, we can relate the input and output Fourier Transforms using the following relationship: Y (jω) = X(jω)H(jω) where H(jω) is the Fourier Transform of the impulse response. Using this rela- tionship, if X(jω) is zero at a particular frequency, Y (jω) must also be zero no matter what H(jω). This is clearly not the case here as X(jω) is zero except at ω0 and −ω0. 2. (2 pts) Give the definition of Fourier transform and Fourier series. Does every signal have a Fourier transform? If yes, prove it. If no, give a counter-example. Solution: The Fourier transform of a sequence x[n] is defined as: X(ejω) = ∞∑ n=−∞ x[n]e−jωn The discrete Fourier series analysis-synthesis pair is expressed as: Analysis equation: X̃[k] = N−1∑ n=0 x̃[n]e −j2πkn N 1 Synthesis equation: x̃[k] = 1 N N−1∑ n=0 X̃[n]e j2πkn N Fourier Transform does not exist for signals whose Laplace Transforms have poles on the open right half plane. An example of such signal is x(t) = etu(t). 3. (2 pts) (THIS PROBLEM WILL NOT BE GRADED) Get the Laplace transform for the following transform and the corresponding region of convergence (ROC): (a) x(t) = sin(ωt)u(t) Solution: sin(ωt) = 1 2j ( ejωt − e−jωt) e−atu(t) ⇔ 1 s + a By the linearity property, the sum of these terms corresponds to the sum of their Laplace transforms. Therefore, L [sin(ωt)u(t)] = 1 2j [ 1 s− jω − 1 s + jω ] = ω s2 + ω2 for σ > 0 (b) x(t) = δ(t− t0), t0 > 0 Solution: X(s) = ∫ ∞ −∞ δ(t− t0)e−stdt = e−st0 for all s 4. (2 pts) Use Matlab to plot y versus t with t = 0 : 0.01 : 5 and y defined as: y = 3e−4t cos(5t)− 2e−3t sin(2t) + t 2 t + 1 Solution: t=0:0.01:5; y=3*exp(-4*t).*cos(5.*t)-2*exp(-3*t).*sin(2*t)+t.^2./(t+1); plot(t,y) xlabel(’t’) ylabel(’y’) 2
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