Quantum Mechanics II: Entanglement and Quantum Statistical Mechanics - Prof. J. E. Moore, Study notes of Quantum Mechanics

Download Quantum Mechanics II: Entanglement and Quantum Statistical Mechanics - Prof. J. E. Moore and more Study notes Quantum Mechanics in PDF only on Docsity! Physics 137B: Quantum mechanics II, Fall 2007 Lecture on quantum statistical mechanics and entanglement This lecture studies some examples of the density matrix formalism for quantum statistical mechanics. We will see that the familiar singlet state of two particles has a property known as “entanglement” that is quite surprising from a classical point of view. Entanglement is one of the basic notions of “quantum information”, Lightning review of the density matrix formalism: The density operator is explicitly written as ρ = N∑ α=1 |α〉Wα〈α|, (1) where |α〉 are some normalized states (not necessarily orthogonal or complete). This is now shown to reproduce the sort of statistical average discussed above. Let’s take an operator A and ask about its statistical expectation. In a particular orthonormal basis, the matrix representation of ρ is ρn,n′ = 〈n|ρ|n′〉 = N∑ α=1 〈n|α〉〈α|n′〉Wi. (2) Now Tr ρA = ∑ n,n′ ρn,n′An′,n = ∑ n,n′,α 〈n|α〉〈α|n′〉Wα〈n′|A|n〉. (3) We can simplify this greatly using the completeness relation for the basis |n〉: completeness requires∑ n |n〉〈n| = 1. (4) Then in the above sum, both the sums over n and n′ just give unity, leaving Tr ρA = ∑ α Wα〈α|A|α〉. (5) Some simple properties of the density matrix that follow from the above definition are Tr ρ = 1 (6) and all diagonal elements are nonnegative, since the diagonal elements are just the probabilities of being in different pure states. We also showed that for a pure state, ρ2 = ρ. You might ask, given the density matrix, how to express the entropy of a quantum system. The logical definition is the von Neumann entropy, defined (if we want to count entropy dimensionlessly, in “bits”) as S(ρ) = −Trρ log2 ρ. (7) For a diagonal density matrix with equal probabilities (this is a mixed state) this reduces to the classical entropy up to a constant. Any pure quantum mechanical state has entropy 0, since a pure state can be converted by a change of basis to a matrix with diagonal elements 1, 0, . . . , 0. 1 This is connected to some recent developments in the theory of “entanglement” of quantum systems. Suppose that a quantum system is made up of two subsystems A and B, and that the whole system AB is in a pure state ρ = |ψ〉〈ψ|. (8) More precisely, the full system’s Hilbert space is a product of A and B Hilbert spaces. We can define the reduced density matrix for subsystem A by a partial trace over subsystem B: 〈φ1|ρA|φ2〉 = ∑ j (〈φ1| × 〈ψj |)|ψ〉〈ψ|(|φ2〉 × |ψj〉). (9) Here the sum is over a basis of the B Hilbert space. This reduced density matrix can give us the results of any measurement of an operator that is of the form ÔA ⊗ 1B, i.e., that can be thought of a measurement on subsystem A. To see this, first note that 〈(ÔA ⊗ 1B)〉 = 〈ψ|(ÔA ⊗ 1B)|ψ〉 = ∑ i,j 〈ψ|(|φi〉 ⊗ |φj〉)(〈φi| ⊗ 〈φj |)(ÔA ⊗ 1B)|ψ〉. (10) Here in the second step we have inserted a version of the identity operator, made from the product basis states; recall that for an orthonormal basis ∑ k |k〉〈k| = 1. Applying the same process again to insert another copy of the identity operator, we get∑ i,j,k,l 〈ψ|(|φi〉 ⊗ |φj〉)(〈φi| ⊗ 〈φj |)(ÔA ⊗ 1B)(|φk〉 ⊗ |φl〉)(〈φk| ⊗ 〈φl|)|ψ〉 = ∑ i,k Ôik ∑ j,l δjl(〈φk| × 〈ψj |)|ψ〉〈ψ|(|φi〉 × |ψl〉)  = ∑ i,k Ôikρki = Tr(ÔAρA). (11) where we have dropped the A and B subscripts in the middle equations. Note that this can be a mixed density matrix even if we started from a pure state for the whole system. As an example, consider the singlet state (| ↑↑〉 − | ↓↓〉)/ √ 2 for a state of two spin-half particles. The reduced density matrix for either particle is found to be ρA = ρB = ( 1/2 0 0 1/2 ) (12) We can confirm by a calculation (do calculation for singlet) that this gives 0 for a product state |ψ〉 = |ψ〉1|ψ〉2, and 1 for a fully entangled state of two qubits (“quantum bits”, i.e., quantum two-state systems). For example, a singlet (| ↑↓〉 − | ↓↑〉)/ √ 2. But thinking more about the singlet state, we seem to have found a physically inconsistent result. The entropy of the whole system is 0 because it is in a pure state, but if we can only perform measurements on one spin, then the density matrix describing those measurements has one bit of entropy. Has the physics somehow changed because we only look at one part of the system? What does it mean if a part of a system looks like a mixed state if in fact the whole system is in a pure state? This type of question was first asked by Einstein, Podolsky, and Rosen in a famous paper in the early days of quantum mechanics. Their idea, more precisely, was to create a singlet pair of particles (there are indeed physical processes that tend to create singlets) and then spatially separate the 2