Download Electrical Eng. Homework 8: Solving Node Equations & Power in Circuits and more Assignments Electrical Circuit Analysis in PDF only on Docsity! Homework 8 Due: Monday, September 12 1 Consider the circuit of Figure 1. (a) Write two node equations in terms of the literal variables in Figure 1 and put them in matrix form. (b) Solve the node equations for the voltages VA and VB when Is1 = 0.5 A, Is2 = 1 A, gm1 = 35 mS, gm2 = 10 mS, G1 = 2 mS, G2 = 3 mS, and G3 = 1 S. (c) Determine V0. (d) Determine the power delivered by each source. (Be careful of the sign.) Friday, September 9, 2011 Figure 1: Model circuits for Problem 1. 2 Consider the circuit of Figure 2. By choosing node C as the reference node, we eliminate a floating voltage source. Write an appropriate set of nodal equations, with node C as the reference node. Solve the nodal equations, specify the voltages 1 VAC , VBC , VDC , and VAB, and the power delivered by the sources. Finally, find the equivalent resistance seen by the current source. Let R1 = 4 kΩ, R2 = 6 kΩ, R3 = 2 kΩ, R4 = 3 kΩ, rm = 1 kΩ, and Is = 60 mA. Friday, September 9, 2011 Figure 2: Model circuit for Problem 2. 3 In the circuit of Figure 3, R1 = 80 Ω, R2 = 10Ω, and µ = 0.75. If Vin = 10 V, find Iin, the power delivered by the independent and dependent voltage sources, and the equivalent resistance, Req, seen by the independent source. Figure 3: Model circuit for Problem 3. 2 R,=8On v= 10@e ua OS
Yne=lO
(2) —\in + ean + a0, == pl Birt) 2
SOT + 10o@Tin_ = hom L
1
| en= Ye Al
RB. = lov(-*a ='Aw-= Pe)
Po = Ov AA = w= Po
Req = Vs 00 ~ |20n= ee | oe
_ tp % oes
HW 08 Supplement - Due Sep 12, 2011
6. Find the current i, in the circuit below (in A):
(1) 0.33 (2)-0.33. (3)2.-— (4) 43 (5)-0.9 (6) 3.33 (7) 0.75
100/9 Q
7. For the circuit shown below, find V,,,(in V).
f;
V.
.&®
\ zor,
=
10Q
A .
NS = y out
22 -
32 10¢
(1) Vout = 50+ Vin
(3) Vout = 150+ Vin
(5) Vout = 250» Vin
(7) Vout = 350 » Vin
(2) Vout = 100 + Vin
(4) Vout = 200 + Vin
(6) Vou = 300 - Vin
10. For the circuit shown below, find Ix.
(054
(B)1L5A
(S)2.5A
(7)3.5A
SA
Ix
aa
We)
1002 200
scat
"| 2000 |
Q2)10A
(4)2.0A
(6)3.0A
12. Find the equivalent resistance R., as seen by the voltage source Vs.
122
6Q
v.E
8Q $ 8Q:
(12 (2)22 (3)3.9 (449
(5)52 (6) 62 (7)72 (8)8Q
13. The loop equations for the circuit shown below are as follows:
Drill
For Ro = 20 Q, find the value of Ry.
Ry R3
MM DPI
Vs (¢ (*) SR, G © I,
(ie (229 (3)32 (4) 42
(3)52 (6) 69 (772 (8)89
i, = Too Va
Solve. for Va
20 i, = G + 3e/,. ly = 3 of 35
7. For the circuit shown below, find V,,,(in V).
f;
V.
.&®
\ zor,
=
10Q
A .
NS = y out
22 -
32 10¢
(1) Vout = 50+ Vin
(3) Vout = 150+ Vin
(5) Vout = 250» Vin
(7) Vout = 350 » Vin
(2) Vout = 100 + Vin
(4) Vout = 200 + Vin
(6) Vou = 300 - Vin
|! 10, + >a) +
= n= Sy
! ‘Ted "S30 10a . °
= 3x etn ny V..)
5 of 35
Find Va — 6 V,
bo i + - (24+
4y,= 2
= S
vy, = 3
Find Vy,
V, = 2(3) 42-86
Vag = YA - Ve = g-3 =]
9. For the circuit shown below, find V,.
(1) 20 V (2)40V
(3) 60 V (4) 80 V
(5) 100 V (6) 120 V
(7) 140 V
——
2 00a 4 a 40h, =
LlOV
b
iss = zy -Lo
NS 30V
S00 7% gov
( = y - Lo)
= Gox Fa/(ee
12. Find the equivalent resistance R., as seen by the voltage source Vs.
122
6Q
v.E
8Q $ 8Q:
(12 (2)22 (3)3.9 (449
(5)52 (6) 62 (7)72 (8)8Q
v.E
)
L>
Reg, |
Esq ——$ 0)
hee= [t+ 606 + ¢f¢
= [6
13. The loop equations for the circuit shown below are as follows:
Drill
For Ro = 20 Q, find the value of Ry.
Ry R3
MM DPI
Vs (¢ (*) SR, G © I,
(ie (229 (3)32 (4) 42
(3)52 (6) 69 (772 (8)89
