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Math 331 Homework 10: Calculating Laplace Transforms using Different Methods, Assignments of Mathematics

Instructions for calculating laplace transforms using two different methods for students in a math 331 course. The first method uses the linearity of the laplace operator and the formula for the laplace transform of exponential functions. The second method uses the formula for the laplace transform of cosh(ct) and the second part of theorem 6.3.2. The document also includes exercises for calculating laplace transforms of specific functions using these methods.

Typology: Assignments

Pre 2010

Uploaded on 08/18/2009

koofers-user-lqi
koofers-user-lqi 🇺🇸

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Download Math 331 Homework 10: Calculating Laplace Transforms using Different Methods and more Assignments Mathematics in PDF only on Docsity! Math 331 – Homework #10 (1) Let b and c be real constants. Calculate L ( ebt cosh(ct) ) using the following two different methods. Show that the two methods give the same answer. Method #1. Using the formula cosh(ct) = 1 2 ect+1 2 e−ct, write ebt cosh(ct) as 1 2 ×(sum of two exponentials) and use the linearity of L and the formula L(eat) = 1/(s− a), where a is a real constant. Method #2. Use the formula for L(cosh(ct)) derived in class together with the first part of Theorem 6.3.2. (2) §6.1, #15. Calculate L(teat) using the first part of Theorem 6.3.2. (3) §6.2, #10. Calculate L−1 ( 2s − 3 s2 + 2s + 10 ) by completing the square in the denominator and using the second part of Theorem 6.3.2. (4) §6.3, #13, #14, #15, #17 with each exponential term replaced by 1. These are the following inverse Laplace transforms. (a) Use the second part of Theorem 6.3.2 to calculate L−1 ( 3! (s − 2)4 ) . (b) Factor the denominator and use partial fractions to calculate L−1 ( 1 s2 + s − 2 ) . (c) Complete the square in the denominator and use the second part of Theorem 6.3.2 to calculate L−1 ( 2(s − 1) s2 − 2s + 2 ) . (d) Either complete the square in the denominator and use the second part of Theorem 6.3.2 or factor the denominator and use partial fractions to calculate L−1 ( s − 2 s2 − 4s + 3 ) . 1
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