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Stat 1222-011 (Professor: Dr. A. Biswas) 4/2/09
ts ID#:
1. A citrus grower’s association believes that the mean consumption of fresh citrus fruits by Americans is lors Van
94 pounds per year. A random sample of 103 Americans has a mean consumption of fresh citrus fruits
of 93.5 pounds per year and a standard deviation of 30 pounds. “4 = meen ton samption & Citvis fruite
(a) {4 pts.) Choose the correct statistical hypotheses to perform the above test. Cleiua> AM Ea
Ay: > 94 versus Hy: p< 94
b) Ho: < 94 versus H, : ju > 94 Ho “Mh 7 4 4 ows Hae MES 94 Chey
c} Ho: w = 94 versus Hy sp #94 ° 1
d) Ho: mu < 94 versus Hy: p> 94. hjt-taled tert
fl-far :
(b) ss pts.) Find the P-value for the above test. > 703, X= 4365) go / Luge aanybfe)
5 Zr X-t 13-5 - 46 , .
° 5028 We Se 17, leff - failed fu.
3625 vu 30/ fies 46 > . : .
a) 1.125 pers? \ 40, P= buen in bff fal
piss KR Ny = uses
{c) (2 pts.) Choose the correct decision.
a) Reject Ho at a = 0.025 because P-value is less than @.
Fail to reject at a = 0.025 because P-value is greater than a.
¢) Reject Hy at a = 0.05 because P-value is less than a.
d) Fail to reject Hp at a = 0.5 because P-value is greater than a.
2. A tourist agency in California claims the mean daily cost for meals and lodging for a family of four is
$ 252. You want to test the claim. In a random sample of 50 families of four traveling in Florida, the
mean daily cost of meals and lodging is $ 260 and the standard deviation is $25. @ fiw: Mr eager.
{a) (2 pts.) Choose the correct statistical hypotheses to perform the above test. . ~
a) Ho: 2 252 versus Hy: < 252 Wo Mest ve i, Mees 2
b) Ho: < 252 versus Hy : > 252 a” —_—
c) Ho: p= 282 versus Hy + jo # 252 eet —~ Vi+y
d) Ho: < 260 versus Hy : p > 260. é fatwa jf iwo- fet led -
(b) (4 pts.) Find the critical values and the appropriate rejection region to test the above claim at 5 ed
a= 02 Reject Ho if Mejectin tetph om ( hoo fa
a) Reject Hp at a = .02 if z > 2.05. E Logon: Qf
b) Reject Hp at a = 02 if z < 2.05. FR ALBE ow B7 233 ay ard!
c} Reject Hy at a = 02 if z < -2.05 or z > 2.05.
Reject Hy at a = 02 if z < -2.33 or z > 2.33.
“Zo Zyz 202%
M
. . a — 2-32
(ce) (2 pis.) Find the standardized test statistic. we SO, Ke eo, 6228 [ lange angle )
rod 2Go- age | 2-26 ‘
Min Ts] iGo -
{d} (2 pts.) | State your decision in the context of the problem.
Aine Ze we does ust fall aa te Paty eben Pup tom
Jen Wert Do wot vey ect Ho Ca Fol b preset He .