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Clapeyron Equation Quiz: Calculating Vapor Pressure and Percentage Error, Quizzes of Physical Chemistry

A quiz on the clapeyron equation, focusing on calculating vapor pressure and percentage error. Students are required to use the given data to calculate dp=dt and the percentage error if it is calculated from the clausius-clapeyron equation instead of the clapeyron equation.

Typology: Quizzes

Pre 2010

Uploaded on 08/09/2009

koofers-user-azr
koofers-user-azr 🇺🇸

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Download Clapeyron Equation Quiz: Calculating Vapor Pressure and Percentage Error and more Quizzes Physical Chemistry in PDF only on Docsity! Chem-433 Quiz #9: 10/28/98 Name: Key Possibly useful information: dp dT = trsH TtrsV p = peVmP=RT d ln p dT = vapH RT 2 p = p exp  vapH R  1 T 1 T   p = p + fusH fusV ln T T  R = 8:3145 J mol1 K1 R = 0:08206 L  atm mol1 K1 1.(10 points) The enthalpy of vaporization of a certain liquid is found to be 14.4 kJ mol1 at 180K, its normal boiling point. The molar volumes of the liquid and its vapor at the boiling point are 0.115 L mol1 and 14.5 L mol1, respectively. (a) Calculate dp=dT (in units of atm K1) from the Clapeyron equation. dp dT = vapH TvapV = 14; 400J=mol (180K)(14:5L mol1 0:115L mol1  0:08206(L  atm)=(mol K) 8:3145J=(mol K) dp dT = 0:0549atm K1 (b) Calculate the percentage error in dp=dT if it is calculated from the Clausius-Clapeyron equation instead of the Clapeyron equation. d ln p dT = vapH RT 2 dp dT = pvapH RT 2 = (1atm)(14; 400J=mol (8:3145J=(mol K)(180K)2 = 0:0535atm K1 The percent error is given by Error = 0:0549 0:0535 0:0549  100 = 2:55%
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