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Resolution of Quiz 4 - Calculus and Analytical Geometry II | MATH 222, Quizzes of Analytical Geometry and Calculus

Material Type: Quiz; Professor: Dynerman; Class: Calculus and Analytic Geometry; Subject: MATHEMATICS; University: University of Wisconsin - Madison; Term: Spring 2009;

Typology: Quizzes

Pre 2010

Uploaded on 09/02/2009

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Download Resolution of Quiz 4 - Calculus and Analytical Geometry II | MATH 222 and more Quizzes Analytical Geometry and Calculus in PDF only on Docsity! Calculus & Analytic Geometry II Quiz #4 - Due Tues. March 3rd, 2009 Math 222 - 306/307 circle your section Spring 2009 Name_Key Answer all of the questions in the space provided. Show all your work and circle your final answer. 1. Compute f° dat Us Iny, dux« kay z cos(In x) tT: 8 du = V° see ude oC eu 6 1” © = LIn] see utdene] = in| 2+ 1 ~ In} deol = In) at03 | 2. Compute [?sinzdx 2 in xd \ Xan dy Sin XOX a Ne a toy drseardy dae2xde ve ~ (0s x ae x \ eos dx a (Woe x OX 4 x Gia nO e-X cant 2X = XSinx ~\ sind = x C08 xb AeSiew bReosy tC SKS AH SX 3. come f 8sint edz J " (Lac bs Cox =) "he = 2 |, (est) Ox 4" sro ‘vay = 8 Q VI Desde bles 42. Ae } TO ir , ‘Ni ba — “\ (A, ox A) CB" Ie dx = A } 6 & sar ~ yee" 4 al eet de - 21tT ~ O L [x t Si0 sin HT = QiT ae Sir 1 Compute | VB) dy AyQ Pa 44 du WSy-D = 7\0) ot \ Be 4 = = SG 3 & =/7Se © y= 7 Sec & toad de = 7\ eer. cbtéae de ce =7 \ Vere tone de - 7 ) baie be - 7 \setet de a) = Jbao~O@ FC ~ _ 7A - se(4) +e = 97% - Séc “(4 + 3 =Sec 6, 3S 9. Rotate the coordinate axes to change 2? + zy + y? = 1 into an equation that has no cross product (xy) term. Then _ the graph of the equation. IL Cob Qt = AC = Ee El =o SAX J, A= a 3 Sin 3 zpiyrygh 7 =| cape R'=0 24’) +a) = se - ri Con “ 2 Gn elliase p20 eA” Elo 704 Fis 10. Find a Cartesian equation for the following set of parametric equations: x = ¢” yo tl. ay Te 11. Replace the polar equation r = —3sec@ by an equivalent Cartesian equation. ra 73 (0 & CWwso=~3 X=-3 12. Find the points of intersection of the pair: r = 1+ siné, r= 1-sin@. Segh both Rng 459 O= J-sine => snes =6 So 4@ehs taksec}- at B=6 oa o= TT Ayioll,, Ds 4ephing, we See Hak dhe gels prteseh ab te ota, 13. Find the area inside the circle r = 3a cos @ and outside the cardioid r = a(1 + cos), a>0- (Cre Gs F at es ae v | [Gee ~ (1 x2o¥ Bes ~ \P 3 1 wm A ~2A oe & do = o (THI ~ r)
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