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FAX NO. = Apr. 13 2683 @6:34PM P1
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Your name
Physics 8A Section 2 Midterm #2
Sefutions
April 10, 2003
Discussion session number / GSi name
1) DON’T OPEN THIS EXAM UNTIL INSTRUCTED TO BEGIN
2) Sit one seat away from anyone else.
3) Do all your work on the page indicated for each problem.
4) Show all work; full credit will require both the correct answer and your reasoning.
5) This is a closed book exam but calculators and one sheet of notes are allowed.
6) Possibly useful equations include:
F =dp/dt=ma Lela
p=mv t=dLdt
Remv/r v=or
K=XotVott+ lat azar
W=Fx 1 = [oom + mh?
U=mgh. K=121¢
U=2 kx’ v, Ay =V_ Ay
K=l2mv pt+l2pv'+pgy = constant
t=la Py = 1000 kg / m?
l=mr
tT=txF
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FROM : :
Fax NO. : Apr. 13 2803 B6:34PM Pe
1) A massless spring has a block of mass m1 = 5 kg attached to it. The mass can
oscillate without friction in a horizontal plane. The period T of oscillation of the
spring/mass combination is T=ns (or 3.14 seconds). Ina first experiment, the
spring/mass combination is compressed by a distance x = 1m, away from its
equilibrium point x = 0, and then released.
x m4 +X
tom ' “\y
xeo
a) Write equations for the resulti sition x velocit? of s mas
function of time.
In a second experiment, the spring/mass combination is again compressed by a distance
x= 1m, away from its equilibrium point, x = 0. A second free mass m2 = 10 kg is then
placed at x= 0. The spring/mass combination is then released.
Ka ha a { Ap
pwr
x=o
b) What is the velocity of mass just before it hits mass m2?
sm sticks to mass m2, what is the maxim inetic energy of the combined
oscillating masses’?
dj If mass m4 collid: stically with mass m2. what vertical hei. 2 is reached b
as it slides up the indicated hill?
Go Te 2m), 8 OD vedas foe
xb) = + aelImebr) cos (2redfee + et)
oe Cmte) er Qonaig en)
vee Cheer) Cos (Dvd leer 4)
VS <2 -2mlg - sm teMc tag )
ow -2d mc . sim (2 -t—n )
sw 2mfs - sin (Ana/e.. )
2
FROM : :
FAX NO. = Apr. 13 2683 66:35PM PS
3) A horizontal bar with mass m1 = 26 kg and length L =3 mis hinged at one end toa
vertical wall, and also held to the wall, at its other end, by a thin, massless wire that
makes an angle @ = 30° with the horizontal. A mass m2 = 30 kg is placed on the
bar.
a) If the wire can withstand a maximum tension TF = 500 N, what is the maximum
distance d that mass m2 can be placed on the bar, away from the wall?
b) What are the horizontal F,, and vertical Fy components of the force on the bar from
the hinge, when the tension in the wire is 500 N?
srey MaePAL OE ME BAR
wyeTeneniseH Equiltbavre «
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—
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Fane =? % vet = ©
o > Fy + ik OF -Wnge tat Fret Ty,
o =f, -250JBN cP Boopy ~ Bons Ry + BON
¥ 250 Sy (>) Fy Zeon (1)
(435-6N)
=>
Euty= 2
oe tev + Tet Cg t Cong t Guy + Lr
oc @+ 6 ~ Goon sd) ~ (Zante: bm) + (28en Bey +
FROM :
FAX NO. + Apr. 13 2083 G6:36PM Pe
4) A block of wood with mass m = 3.67 kg has a GENSILY Dyoog = 6.06 ¥ 10° kg/m? itis
to be loaded with lead, with density Py= L13 x 107 kg/m’, so that the wood will
float in water with 90% of its volume suhmerged below the level of the water.
fin tie
a) If the lead is attached to the top of the wood, what mass of lead is needed?
b) If the lead is attached to the bottom of the wood, what mass of lead is needed?
@) Vooae= "past
Fe
i Te ~ Mume-g Meg =o
29 Vwed Curate §— Iuscou gy. “MeL “3 = O
Mandy, Mesa.
O9f Muosd \ _ = My,
[ eset Pusoter - Mitood Pb
‘pe -
b) +
4 Fa — Mood. 4 MRED FO
Fondly, MA /
ames or (Voteal) + ver) Pusster 3) ~ PA tract ype: =O
Wed =
Ca Zany t ne ater - Winoed! = Mee,
Coad Gro Co em
H
2.9 Mwced vip, Coster
Cony Comrer + pe a — Missed Wey
o4 M peed Curcher ~ Muood
FROM = :
Fr NO. = Apr. 13 2443 86:36PM P?
5) A large diamcter tank on a tower ig filled with water to a depth d= 1m. The tank
has a bole in the bottom with diameter d, = 2 em.
a) What is the volume of water that flows out of the hole ina time of 10s?
a) Ifthe water flows straight down from the bottom of the tank, at what distance from the
bottom of the tank does the diameter of the water stream ua} 1 cm?
@) Remote” Be
Re Eeve + Coy, =Pat blue CS.
Fizfizfetm, tied, yee, WFO
“Peston + OF Pande 9-4 = Poms Bae + 2
2x4 = Ye
{ao ms. = V2.
Volume = Votoms fm # ime 3
= Aa, € (9.02m) ©. ve fs foee
“po EZ Mm}
we aad AM: = ArV2.
Conant fang” Co-olmy Th Va
Ye = Ae ms
pong oases: VO yareza CQ-d)
| (SBF (er) - 2 Con)
Ay= 15m.
ous the hele.