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Solving a First Order Ordinary Differential Equation (FOODE) with Given Initial Conditions, Quizzes of Advanced Calculus

The University of Texas at Austin Advanced Calculus

Prof. Klaus R. Bichteler

The solution to a first order ordinary differential equation (foode) with the given initial conditions. The equation is (2y + 2x - π cos(πx)) dx + (2x + 2y) dy = 0, with y(0) = 1. Five different initial conditions for y(1), and the correct answer is determined by finding the integrating factor and the general solution of the equation. The solution is then used to find the value of y(x) for the given initial conditions.

Typology: Quizzes

2010/2011

Uploaded on 10/07/2011

hoang0100 🇺🇸

3 documents

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Download Solving a First Order Ordinary Differential Equation (FOODE) with Given Initial Conditions and more Quizzes Advanced Calculus in PDF only on Docsity! Solve the FOIVP (2y + 2x− π cos(πx)) dx+ (2x+ 2y) dy = 0 , y(0) = 1 . (1) y(1) = π2 (2) y(1) = π (3) y(1) = −1 (4) y(1) = −π (5) y(1) = 0

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