Scientific Notation, Metric System, & Unit Conversion Review ..., Slides of Physics

Download Scientific Notation, Metric System, & Unit Conversion Review ... and more Slides Physics in PDF only on Docsity! Physics 151 Scientific Notation, Metric System, & Unit Conversion Review Worksheet Scientific Notation 1. Rewrite the following numbers in scientific notation, in simplest form. Include units. Use appropriate significant figures! a. Altitude of summit of Mt. Ka‘ala (highest point on O‘ahu): 4020 ft = b. Altitude of summit of Mauna Kea: 13,796 ft = c. Thickness of a human hair: 0.015 cm = d. Wavelength of reddish light: 0.0000007 m = e. Height of your instructor: 1.80 m = f. Number of galaxies in the universe: 1 trillion galaxies = g. Age of the universe in seconds: 430,000,000,000,000,000 s = h. Volume of a hydrogen atom: 0.000 000 000 000 000 000 000 000 621 cm3 = 2. Calculate the following, and write your answer to each in scientific notation. Try to do (a)–(i) first without the aid of your calculator, then check your answers by redoing them with your calculator. Assume that parts (a)–(h) contain exact numbers with infinite precision; for parts (i)–(n), express only the appropriate number of significant figures in your final answer. [Note that (b), (c), (g), (l), and (m) contain division signs, not plus signs.] a. 1010 × 104 = b. 1010 ÷ 104 = c. 1010 ÷ 10–4 = d. 1010 + 104 = e. 1010 − 104 = f. (2 × 105) × (3 × 1012) = g. (3.5 × 1017) ÷ (7 × 108) = h. 107 − (3 × 106) = i. (42.3 × 10–5) + (5.77 × 10–4) = j. (34.9 × 106) × (212 × 10–15) = k. (0.88 × 10–3) × (6.3 × 10–10) = l. (9.876 × 1035) ÷ (5.4321 × 10–13) = m. mass of Earth ÷ mass of Moon = (5.974 × 1027 g) ÷ (7.348 × 1025 g) = n. mass of Earth − mass of Moon = (5.974 × 1027 g) − (7.348 × 1025 g) = Powers of Ten 3. Insert the correct metric prefix abbreviations (be careful to distinguish upper case from lower case!): 10–2 m = 1 _____m 109 y = 1 _____y 103 W = 1 _____W 10–3 m = 1 _____m 106 W = 1 _____W 10–6 s = 1 _____s 10–9 m = 1 _____m 103 g = 1 _____g 109 bytes = 1 _____B 106 Hz = 1 _____Hz 10–12 s = 1 _____s 1012 bytes = 1 _____B (units: m = meter; g = gram; s = second; Hz = hertz, a unit of frequency; y = year; W = watt, a unit of power; B = byte, a unit of computer information) 4. Match each of the following length units to the distance that it is best or most frequently used to describe: A. Size of an ant _____ 0.1 nm = 1 Å B. Size of a person _____ 100 nm = 1000 Å C. Distances between neighboring stars _____ 100 µm D. Diameter of human hair _____ 1 mm E. Size of an atom _____ 100 cm = 1 m F. Size of viruses and small bacteria _____ 1 km G. Distances within our Solar System _____ 108 km H. Distances around Oahu _____ 1013 km Significant Figures 5. How many significant figures are represented in each of the following numbers? a. 579.420 b. 3.14159265 c. 2 × 1011 d. 50. e. 3800 f. 5.60 × 1048 g. 243. h. 9.0000 × 10–9 i. 0.00000030 j. 8 Unit Conversions 6. a. Starting with your age in years, calculate your age in days. (You do not need to be exact: forget about leap days, etc.) b. Approximately how many days long is your total life expectancy? 7. Use your weight in pounds (while standing on the surface of the Earth) to calculate your mass in kilograms and in grams. (1 kg weighs approx. 2.205 lb on the surface of the Earth) This is a useful thing to know, since almost every other country in the world uses kilograms! Scientific Notation, Metric System, & Unit Conversion Review Worksheet SOLUTIONS 1. a. 4.02 × 103 ft (or 4.020; it is unclear whether the final zero is significant) b. 1.3796 × 104 ft c. 1.5 × 10–2 cm d. 7 × 10–7 m e. 1.80 m (this is the same as writing 1.80 × 100 m) f. 1 × 1012 galaxies (or simply: 1012 galaxies) g. 4.3 × 1017 s (or 4.30, or 4.300, etc., although there are probably only 2 sig. figs) h. 6.21 × 10–25 cm3 2. Assume the values in parts (a)–(h) are exact numbers with infinite precision: a. 1010 × 104 = 10(10 + 4) = 1014 b. 1010 ÷ 104 = 10(10 – 4) = 106 c. 1010 ÷ 10–4 = 10(10 – –4) = 1014 d. 1010 + 104 = 1.000001 × 1010 e. 1010 − 104 = 9.99999 × 109 f. (2 × 105) × (3 × 1012) = (2 × 3) × (105 × 1012) = 6 × 10(5 + 12) = 6 × 1017 g. (3.5 × 1017) ÷ (7 × 108) = (3.5 ÷ 7) × (1017 ÷ 108) = 0.5 × 10(17 – 8) = 0.5 × 109 = 5 × 108 h. 107 − (3 × 106) = (10 × 106) – (3 × 106) = (10 – 3) × 106 = 7 × 106 For parts (i)–(n), observe significant figures: i. (42.3 × 10–5) + (5.77 × 10–4) = 1.000 × 10–3 j. (34.9 × 106) × (212 × 10–15) = 7.40 × 10–6 k. (0.88 × 10–3) × (6.3 × 10–10) = 5.5 × 10–13 l. (9.876 × 1035) ÷ (5.4321 × 10–13) = 1.818 × 1048 m. (5.974 × 1027 g) ÷ (7.348 × 1025 g) = ratio of mass of Earth to mass of Moon = 81.30 (or: 8.130 × 101) n. (5.974 × 1027 g) − (7.348 × 1025 g) = difference of mass of Earth and mass of Moon = 5.901 × 1027 g 3. 10–2 m = 1 cm (centimeter) 109 y = 1 Gy (gigayear) 103 W = 1 kW (kilowatt) 10–3 m = 1 mm (millimeter) 106 W = 1 MW (megawatt) 10–6 s = 1 µs (microsecond) 10–9 m = 1 nm (nanometer) 103 g = 1 kg (kilogram) 109 bytes = 1 GB (gigabyte) 106 Hz = 1 MHz (megahertz) 10–12 s = 1 ps (picosecond) 1012 bytes = 1 TB (terabyte) 4. A. Size of an ant ___E__ 0.1 nm = 1 Å B. Size of a person ___F__ 100 nm = 1000 Å C. Distances between neighboring stars ___D__ 100 µm D. Diameter of human hair ___A__ 1 mm E. Size of an atom ___B__ 100 cm = 1 m F. Size of viruses and small bacteria ___H__ 1 km G. Distances within our Solar System ___G__ 108 km H. Distances around Oahu ___C__ 1013 km 5. a. 6 b. 9 c. 1 d. 2 e. 2 (or 3 or 4… it’s ambiguous!) f. 3 g. 3 h. 5 i. 2 j. 1 6. a. Assuming an age of 20. years: (20. y) × (365 d / 1 y) = 7300 d b. Assuming an 80.-year life expectancy: (80. y) × (365 d / 1 y) = 29,000 d (rounded to 2 significant figures) 7. Assuming a weight of 150. pounds: (150. lb) × (1 kg / 2.205 lb) = 68.0 kg 8. a. 1.0000 m/s = 2.2369 mi/h, or 1.0000 mi/h = 0.44704 m/s b. 1.5 Tb = 1500 Gb or 1.5 × 103 Gb 1.5 Tb = 1,500,000 Mb or 1.5 × 106 Mb 1.5 Tb = 1.5 × 109 kb 1.5 Tb = 1.5 × 1012 b 45 µg = 0.045 mg or 4.5 × 10–2 mg 45 µg = 45,000 ng or 4.5 × 104 ng 45 µg = 4.5 × 10–8 kg 550 nm = 5.5 × 10–10 km 6328 Å = 632.8 nm 15 ps = 0.015 ns or 1.5 × 10–2 ns 15 ps = 1.5 × 10–5 µs 15 ps = 1.5 × 10–8 ms 14 Gy = 4.4 × 1017 s 1 km2 = 1,000,000 m2 or 106 m2 1 m2 = 10,000 cm2 or 104 cm2 1 km2 = 1012 mm2 1 m3 = 1,000,000 cm3 or 106 cm3 1 m3 = 1,000,000,000 mm3 or 109 mm3 200 cm3 = 200 mL 1 km3 = 1,000,000,000,000 L or 1012 L 1.000 atm = 1013 mbar 100. km/h = 27.8 m/s 1 kg·m/s = 100,000 g·cm/s or 105 g·cm/s 9.80 kg·m2/s2 = 98,000,000 g·cm2/s2 or 9.80 × 107 g·cm2/s2 330 g·cm2 = 3.3 × 10–5 kg·m2 9. a. Yes. One could devise an experiment to test the relative speed of light in various media. b. No. This is a subjective statement. c. Yes. This is a statement that can be tested and, if contradicted by measurements, falsified. d. No, unless there is some way that the hypotons’ existence can be detected. e. No. This is a subjective statement. f. Yes. A survey can be performed to support or disprove the statement (to within a desired level of certainty). g. No. There is no possible test that could be performed that might disprove the statement. 10. a. If the Earth is spherical, then ships should disappear over the horizon bottom-first and mast-last. Aristotle also deduced that the Earth must be spherical since lunar eclipses always show the shadow of the Earth as a circle, no matter the direction in which the eclipse happens. b. If the Earth were not spinning, we would need a new explanation for the Coriolis effect and Foucault’s pendulum. c. If the Earth were not orbiting the Sun, we would need a new explanation for the annual cycle of parallax motion of the nearest stars.