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Simple Resistive Circuits - Introduction to Electrical Engineering - Lecture Slides, Slides of Electrical Engineering

These are the Lecture Slides of ntroduction to Electrical Engineering which includes Transport or Present, Convert Energy, Electrical Systems, Major Classifications, Communications Systems, Computer Systems, Control Systems, Electromagnetics, Electronics etc. Key important points are: Simple Resistive Circuits, Applications, Calculating Resistance, Conductor, Cross Section, Temperature Coefficient of Resistance, Metallic Conductors, Increased Temperature, Linear Increase, Reference Temperature

Typology: Slides

2012/2013

Uploaded on 03/22/2013

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Download Simple Resistive Circuits - Introduction to Electrical Engineering - Lecture Slides and more Slides Electrical Engineering in PDF only on Docsity! Circuit Analysis Lecture 03 - Simple Resistive Circuits and Applications Docsity.com Calculating Resistance Area, A l lR A ρ ⋅ = 6 6 1.67 10 2.70 10 cu al cm cm ρ ρ − − = ⋅ Ω ⋅ = ⋅ Ω ⋅ When conductor has uniform cross-section Docsity.com Resistors in Parallel (1/2) I s R1 R2 + V1 - I 1 I 2+ V2 - + Vs - + Vs - I s Req 1 1 1 VI R = 22 2 VI R = By KVL: Vs = V1 = V2 By KCL: Is = I1 + I2 By Ohm’s Law: and Combine: 1 2 1 2 1 2 1 1 s s s eq VV VI V R R R R R   = + = + =    Docsity.com Resistors in Parallel (2/2) 1 2 1 2 eq R RR R R = + 1 2 1 1 1 1 eq nR R R R = + + + 1 2eq nG G G G= + + + For two resistors: For many resistors: In terms of conductance: Docsity.com Voltage Divider Circuit Vs R1 R2 + V1 - + V2 - M easure V2 I ( )1 2sV I R R= + 1 2 sVI R R = + 2 2 2 2 1 2 1 2 s s V RV I R R V R R R R = ⋅ = = + + Docsity.com Current Divider Circuit I s G1 G2 + vo - i1 i2 1 2 1 2 1 2 s o Ii iv G G G G = = = + 2 2 2 1 2 1 2 1 1 1s s G Ri I I G G R R = = + + 2 1 2 1 2 1 2 1 2 1 2 1 1 1s s R R R Ri I I R R R RR R = = ++ If there are only two paths: In general: 1 2 n n s n Gi I G G G = + + + Docsity.com D’Arsonval Meter Movement • Permanent Magnet Frame • Torque on rotor proportional to coil current • Restraint spring opposes electric torque • Angular deflection of indicator proportional to rotor coil current S N Docsity.com D’Arsonval Voltmeter • Small voltage rating on movement (~50 mV) • Small current rating on movement (~1 mA) • Must use voltage dropping resistor, Rv Rv + Vd'A - + VRv -+ Vx - Id'A Docsity.com D’Arsonval Ammeter • Small voltage rating on movement (~50 mV) • Small current rating on movement (~1 mA) • Must use current bypass conductor, Ga Ga + Vd'A - IGa Id'AIx Docsity.com Example: 1 Amp F.S. Ammeter Note: d’Arsonval movement has conductance of 0.02 S Scale chosen for 1.0 amp full deflection. Ga = 19.98 S has ~50.050 mΩ resistance. 19.98 S + 50 mV - 999 mA 1 mA 1.0 A Docsity.com Example: 10 Amp F.S. Ammeter Scale chosen for 10 amp full deflection. Ga = 199.98 S has ~5.0005 mΩ resistance. 199.98 S + 50 mV - 9.999 A 1 mA 10 A Docsity.com Example: Voltage Measurement Measured Voltage: 10045 8.9286 100400 1 100 10 oV V k Ω = =  Ω Ω + + Ω Ω  8.9286% 1 100% 0.794% 9.0 VError V   = − = −    Docsity.com Another Voltage Measurement (1/2) True Voltage: (If voltmeter removed) 1045 9 50o kV V V k Ω = = Ω 45 V 40 kΩ 10 kΩ + Vo - 10 kΩ volt- meter Docsity.com Another Voltage Measurement (2/2) Measured Voltage: 1045 5.0 1040 1 10 10 o kV V V kk k k Ω = =  Ω Ω + + Ω Ω  5.0% 1 100% 44.44% 9.0 VError V   = − = −    Docsity.com Another Current Measurement (1/2) True Current: (If ammeter replaced by short circuit) 255 1.0 125o mI A A m Ω = = Ω 5A 100 mΩ 25 mΩ 50 mΩ Ammeter Io Docsity.com Another Current Measurement (2/2) Measured Current: 255 0.7143 175o mI A A m Ω = = Ω 0.7143% 1 100% 28.57% 1.0 AError A   = − = −    Docsity.com Measuring Resistance • Indirect – Measure Voltage across Resistor – Measure Current through Resistor – Calculate Resistance (Inaccurate) • d’Arsonval Ohmmeter – Very Simple – Inaccurate • Wheatstone Bridge (Most Accurate) Docsity.com Wheatstone Bridge Vg Rg R1 R2 R3 Rx a b c d + Vab - I 1 I 2 I 3 I x I ab 2 3 1 x R RR R ⋅ = Vab= 0 and Iab= 0 Vad = Vbd I1 = I3 I2 = Ix R1I1=R2I2 R3I3=RxIx Docsity.com Example: Wheatstone Bridge 1 kV 100 Ω 150 Ω 300 Ω 450 Ω 900 Ω a b c d RqI 150 300 450 900 Ω Ω = Ω Ω I = 2 A Docsity.com
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