Solved Problems on Time and the Hyetograph - Assignment 3 | CVEN 463, Assignments of Hydrology

Download Solved Problems on Time and the Hyetograph - Assignment 3 | CVEN 463 and more Assignments Hydrology in PDF only on Docsity! CVEN 168 — Kmenote *F Seorieds /. Sommer Bey S= tho td S, = 0.0 - tio = fF Paty Le oT ag, = ste! (0-440 + o0edge,) | Tae * S0*E = 16.72 1993K Sst 8S mb ab Tate (fam Table Kz, Hf) a 0.65 -38.( = 22.8mb b= G.908-10°°) - 699-8)4: (onder ovcoy9 (2r8)) = 33.7 ey Ls 008 33.72 = so “Yardy Me attes 5 Tas tes 22.9% = 297% 0K m= (4.908-t0°3) » (297.0)1 - (0.97) = 37.0 “eg On = Cp tutta 5 . Ola = G 1468: 00° *)( see) ( 25)(293.2) = 92068 mJ Tin = GBF = 200°C = Z93.2K . Qt = Ce (1 Voot Tok = (41663 fo *)( 100 )(725.)(29F. 0 Qc © LSS FES OI AQ = Cp (Sia Tend ~ Seat Tree) Assume Tend © Trhet © Tonk 5 Sed See HAS =H Wat . oe (41865-10°) (/1)( 294.2) [#- sas] = — 62194 ms /. Ceantrawed) he 2.¢0f - o.00236/ (28.8) = 2.44 “Thy . p _ Ta ~ Tae Be 0.60 jee “ely ee 5 es (ae 23.9%) * 2.968 ES 29.08 wb (reso) _(23.9°C) — (24.3 "c) _ Be oe reo (22. ¢@mi\—(zz-amb) 9-2 487 - VA 0C5 TNS SF C27 (25.0~7.#) + (332-10) —G7.0) + 92065 — ee (2.44) Goo) (7 4 ~ 0.2487) Ee #8910? fee 7.9 wm /eeg = 0.3/ in [ede S= [3.6 mf S_ + e08 sb0 = 1.0 Yo dg L® eg (reser = 10%) = /2.t8mb | €* /2.28-0.95 = 9. 2/mb Le 6-903-10*)(288.20)" (0. #40 + 0.0099 @.21)) = 24.86 Vir Lo = o.0t 248 = 0.2 hed a r dq Mts Taz GME = h.1eC = 289.3K m= (4. 903-70") (299.3 04 (0.99) = 33.3 Ya ag _E= APEC /edag = /72 mo dey = 0-68 in [dag Lenmen 7 tn ber — che fee a ABE Fe Te = fol p SF 008% ey We ober Me Swe Rip SAF oh (i?-0- 1.04 2480.7) - Lites ~ 62580 ~ 96 397 2 es Crdoy) + 6,082 + 0.0661 (2-4) (120) © 06 ef (6.¥8-10°4)( + eee nT ©. 082 + 0.060] ZY E= CV ody = Bf me {dag = o¥8 (o/b &. Fan A Svurvoundd dys bare On te “Ge B 3 up sird fetek Ae 250m RHE SSH | Wind = Ml mile = VIZ Covvec tion feb = 0.59 fan 8 » Case B pean fokd 90m, Corr, factor = 0.6/ Pan C, Surrounded ba grun punkred Cree ) “Ce A" op wind pee % 200m > Serceneal , 50 intrtate 4 abut fo- 20% (se 15%) Comm. fase fr = O26 -s1r = 28% Pan D, Case A, cpuied fob 2 /S0m Screened , tare. factor = 6.96. f1r > 0.86 Ran € > Gents hee bee deiaking wate) Diregard. Pan Measurement (in) Qerccled Esbnate (in) a O.ss7 ©.32 8 0.94% 0.29 c 6.357 0.30 » O.3F 0.3h € 8.67 6. fr 08s, Pr hem > Kept Ott a 3 Finik = 0.253 Ce 0.85 (ys 0.89 M/E, C$- Giant) (0.735~ 0.255) (21. em) Ba NF pei Bem Ge -) 2.89 Ho Kt ( ory Oy, >) t= Fe OFhem o.8lh ——— 7; P = tt ea che = : ns Fine feat renopf betas. Tue wags poss: ble. - mol . : “ fod voruf © bes solv tion « f Te apie fan gente Cpe to nea! method) : Sule fe 6” as fine & inf bm he ‘ under iw oll pode Con dita . ro _t . 0. FZem ¢ “(ed =) he ve on) ~ (21 Ben\(ossr-0.253) sf * ciel t's 0.43 bes Then fr bz (0 hes ; pud F foum : Gt (Eade tp) = Fe Cfo Ouit) +n [ ‘Gay | £ CM (o- o.8i+ 0.48) = F ~ G1 3\(0.¥ss-0.255) staf Cucvaiaa | 3U%3 = F —3,BFF. [nu (ssl fo f. (ean haved) Net , we want f find when comulabve P would gen / %. Pe ct =e fe pmdiig , Ba i-ty 5 The, t= Bee ~ Flin tp 0.35 Yp = /3,. 74 hes and fhe beginning f the balan ced taf bearer Curve , tp, would be te = tp fp! = [4-230 © 4.39 he, Lf the Shem last val 10 hus ) then pong weld ast tere be fave the end of Yhe Sform . 7 hes, rune aS Bee der fase cand tions . "W 3g. _ Ta tertaption ae T= a+ op” : Pine at oor b=0.20 cree _ Fron hethgrch , tobe! P= VLE in ~L18 in At = 0.05 + oof grs)™ = 0.46 iy At Bim, 4b hes , = oben se inkeces fon tales al porcedp op * Hat time. Tefitrakin, Curve ~ Hoe ton _fz20 Me Lvot “Ye Be hteh rT 7 wt —~ — Valabened Cree _ $y (te) EGA) The erin thet the 9 ofilhinifan curve can ae 2.0 - bain cs t= hitb hes the ond of Mehruptin. os 0.85 0.64 The tnital (afr thn rk 20 he 1x abeve _ /0 0. 4a 0-46 = 0F the a Hal tne, So Fhe core ast — LS A be bahanced. 2.0 ois /.20 Ginee 6 mt consheak 4 Siimpphe 2s o.IL Lt peralgthta/ Soluton 4's Afelt. ZH & 3.0 oll 1.32 pets taster fo chen he on % 6 - ae 0.t0 /.3t / Land accrotebe hea ten foe ho ‘ ‘ The geal of The ork » a "é Aol $, Such ThA blentin befee pedi an ss trate cap bir prtejaitelic befaee poadicg are trl Geel one: ‘ gv # g (Z 3. (continud,) thre, we tp Ty 08 te st pralen dues 4 pott-iakecephion Tdernten tp, he) tlre) Fda) BGx) ft / 16 {Fo 0.40 ode Fo >P 30 increase ep, z 2.0 2.06 Out aw Fa < Fp, So cleewente tp, 3 LS 2.o 0.6% 0.64 Clase ensegh / Oe, tp us at 2.ohes. Runoff bays. Za fol te fh nk £ reaches a content inhe of 0.00 the (fe) at 8. hows mf tee oe 4, which andld be B.S thse Se hrs. Resafell rate ckerecses bel ore "Vi nt Ame. Six hes , So runoff would end tan. Tote iapitba hon dor rag shem wuld be Sum f E (ty'> Hoses) to Cot fast oshes of rernfadt Cethen é<f) . ' ‘ Go-e. ale ~ EBONY F(t 4.0les) = (01 BY Yoh) + eS (1 - ») 1.920 Last O.Shrs f fr @.es Z)(0she) = 0.085 in ~~ 0.0304 Tobe Sofi lbn then = 1 ISin Losses = Tater cop han + Lfilbahon + Depression Sforage = Ofbim + fT + 0.051, = ANISb ng Kon f = Pp bss = $280 —/9L oy = 2.382 in See rept pt pr dixgrem f fostes on Ayetgraph .