Stoichiometry of the reaction between sodium hypochlorite | CHEM 1045, Lab Reports of Chemistry

Download Stoichiometry of the reaction between sodium hypochlorite | CHEM 1045 and more Lab Reports Chemistry in PDF only on Docsity! Date preformed: 10/17/2008 Name: Kyra Mingus Date submitted: 10/24/2008 Partner: Shane Duncan Instructor: Sen Stoichiometry Objective  To determine the stoichiometry of the reaction between sodium hypochlorite (NaClO) and potassium iodide (KI) in aqueous solution. Experimental Data Mass of KI: 16.6 g Volume of NaClO, ml Volume of KI, ml Temperature of NaClO, °C Temperature of KI, °C Final Temperature, °C 45 5 21.42 20.10 24.34 40 10 21.40 20.42 27.89 35 15 21.41 20.53 29.02 30 20 21.40 20.64 27.87 25 25 21.43 20.74 26.54 20 30 21.41 20.84 25.62 15 35 21.41 20.87 24.20 10 40 21.42 20.91 23.00 5 45 21.47 20.76 21.86 Sample Calculations: Mass of KI= 16.6 g Volume of NaClO in Solution: M1V1 = M2V2 (.762)(V1)=(.40)(250 ml) V1 = 131 ml NaClO Mass of KI Mm KI= 161 g/mol (.4M)(.250L)=.100m KI (166 g/mol) =16.6 g KI Mole fraction NaClO (Volume NaClO)/(Volume NaClO+Volume KI) Mol Fraction= (45 ml)/ (45 ml + 5 ml) = .9 Tinitial= (T1V1)+(T2V2) / (V1+V2) = (21.42 °C *45 ml) + (20.10 °C *5 ml) / (45 ml + 5 ml) = 21.29 °C ΔT = (TT = (Tfinal – Tinitial) 24.34 °C – 20.10 °C ΔT = (TT = 4.24 °C PEAK OF GRAPH: 12.47x - .3 = -31.3x + 32.51 X = 0.749 Y = 12.47(0.749) -.3 Y =9.04 Peak = (0.749, 9.04) VOLUMES USED: 0.749 = a/ (a+b)= a/ 50 ml a= Mol NaClO NaClO ml= (0.749 * 50 ml) = 37.45 ml b= (1-a) = (1-.749) = .251 Mol KI KI ml = (50 ml – 37.45ml) = 12.55 ml a/b = (.749/.251) = 2.99 Mol NaClO to Mol Ki Results and Conclusions Volume NaClO, ml Volume KI, ml Mol Fraction Initial Temperature, °C Final Temperature, °C ΔT = (TT °C 45.0 5.0 0.90 20.10 24.34 4.34 40.0 10.0 0.80 20.42 27.89 7.47 35.0 15.0 0.70 20.53 29.02 8.49 30.0 20.0 0.60 20.64 27.87 7.23 25.0 25.0 0.50 20.74 26.54 5.80 20.0 30.0 0.40 20.84 25.62 4.78 15.0 35.0 0.30 20.87 24.20 3.33 10.0 40.0 0.20 20.91 23.00 2.09 5.0 45.0 0.10 20.76 21.86 1.10 Equation of increasing line: Y= 12.47x-.3 Equation of decreasing line: Y= -31.3x+ 32.51