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Chemistry Practice Problems: Balancing Equations and Finding Empirical Formulas, Exercises of Chemistry

A set of chemistry practice problems focusing on balancing chemical equations and determining empirical formulas of compounds. The problems involve writing formulas for various compounds, providing names for them, and writing the products formed when each reaction takes place.

Typology: Exercises

2012/2013

Uploaded on 01/01/2013

shabo-rani
shabo-rani 🇮🇳

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Download Chemistry Practice Problems: Balancing Equations and Finding Empirical Formulas and more Exercises Chemistry in PDF only on Docsity! s 1) Complete and/or balance the following reactions, 2 3 4 3a) FeS + O ------> Fe O + SO 2 2 4 2b) CO + H O ------> CH + O 2 5 2 3 4c) P O + H O ------> H PO 2 4 3d) Cl + CH ------> CHCl + HCl 2 4 3 2 4 3 2e) H SO + Al(OH) -----> Al (SO ) + H O 3 2 2f) NH + O ----> NO + H O 2 2 2 3g) H S + O ----> H O + SO 3 2 3 4 4 3h) Pb(NO ) + H AsO ----> PbHAsO + HNO 2i) Na + H O ----> 2j) Li + N ----> 2k) C + Cl ----> 2 4 3 4l) CaCl + (NH ) PO ----> 3 8 2m) C H O + O ----> 2 3 4o) CaCl + H PO 2) Write the formulas for the following compounds a) Titanium (IV) Chloride b) Tetraphosphorous decaoxide c) Sodium Carbonate d) Calcium Fluoride e) Iron (III) Nitrate f) Iodine Pentafluoride g) Aluminum Hydroxide Docsity.com 3) Please provide names for the following compounds. 2a) ZrO 4 3 4b) (NH ) PO 2c) Na S 4d) SeF 4e) CCl 3f) CaCO 2 3g) Co O 4) Please write the product formed and balance each reaction 2a) P + O ----> 2b) Mg + N ----> 8c) Sc + S ----> 2d) Li + N ----> 2 2e) N + H ----> 5) Please write the net ionic reaction that occurs when the following compounds are mixed. Barium Nitrate and Ammonium Carbonate Aluminum Nitrate and Sodium Hydroxide Lead Acetate and Potassium Iodide Silver (I) Nitrate and Sodium Dichromate Mercury (I) Perchlorate and Sodium Chloride Ammonium Phosphate and Calcium Chloride Phosphoric acid and Ammonium Hydroxide 6) Please complete and balance the following reactions when the each compound is combusted with oxygen. 2 3Fe S 3NH NaCN 3CH SH 3 2AgCH CO Docsity.com 3) Please provide names for the following compounds. 2a) ZrO Zirconium (IV) Oxide 4 3 4b) (NH ) PO Ammonium Phosphate 2c) Na S Sodium Sulfide 4d) SeF Selenium Tetrafluoride 4e) CCl Carbon Tetrachloride 3f) CaCO Calcium Carbonate 2 3g) Co O Cobalt (III) Oxide 4) Please write the product formed and balance each reaction 2 2 5a) 4 P + 5 O ----> 2 P O 2 3 2b) 3 Mg + N ----> Mg N 8 2 3c) 3 Sc + 3/8 S ----> Sc S 2 3d) 6 Li + N ----> 2 Li N 2 2 3e) N + 3 H ----> 2 NH 5) Please write the net ionic reaction that occurs when the following compounds are mixed. 3 3Barium Nitrate and Ammonium Carbonate Ba + CO ----> BaCO 2+ 2- 3Aluminum Nitrate and Sodium Hydroxide Al + 3 OH ----> Al(OH) 3+ - 2Lead Acetate and Potassium Iodide Pb + 2 I ----> PbI 2+ - 2 7 2 2 7Silver (I) Nitrate and Sodium Dichromate 2 Ag + Cr O ----> Ag Cr O + 2- 2 2 2Mercury (I) Perchlorate and Sodium Chloride Hg + 2 Cl ----> Hg Cl 2+ - 4 3 4 2Ammonium Phosphate and Calcium Chloride 3 Ca + 2 PO ----> Ca (PO ) 2+ 3- 2Phosphoric acid and Ammonium Hydroxide H + OH ----> H O + - 6) Please complete and balance the following reactions when the each compound is combusted with oxygen. 2 3 2 2 3 3Fe S + 6 O ----> Fe O + 3 SO 3 2 2 5 22 NH + 4 O ----> N O + 3 H O 2 2 2 2 52NaCN + 5 O ----> Na O + 2 CO + N O 3 2 2 2 3CH SH + 7/2 O ----> CO + 2 H O + SO 3 2 2 2 2 22 AgCH CO + 4 O ----> Ag O + 4 CO + 3 H O Docsity.com 7) When a 10.0 gram sample of an unknown organic acid is subjected to combustion analysis, 2 221.2 grams of CO and 3.25 grams of H O are produced. What is the empirical formula of the compound? 2 221.2 g CO = 0.4818 mol CO ==> 0.4818 mol C 0.4818 mol C x 12 g/mol = 5.7816 g C 44 g/mol 0.3610 mol H x 1 g/mol = 0.3610 g H 6.1426 g Total 2 23.25 g H O = 0.1805 mol H O ==> 0.3610 mol H 10 g - 6.1426 g = 3.8574 g of oxygen 18 g/mol 3.8574 g O = 0.244 mol O 16 g/mol 0.4818 mol C = 2 C 0.3610 mol H = 1.5 H 0.2440 mol O 1 O 0.2440 mol O 1 O 2 1.5 2 1.5 4 3 2The formula is C H O but you cannot have a fraction so, 2(C H O) = C H O 8) An 11.0 gram sample of a solid unknown was burned in oxygen producing 5.00 grams of water and 16.29 grams of carbon dioxide. What is the empirical formula of the compound? 2 216.29 g CO = 0.3702 mol CO ==> 0.3702 mol C 0.3702 mol C x 12 g/mol = 4.4424 g C 44 g/mol 0.5556 mol H x 1 g/mol = 0.5556 g H 4.998 g Total 2 25.00 g H O = 0.2777 mol H O ==> 0.5556 mol H 11 g - 4.998 g = 6.002 g of oxygen 18 g/mol 6.002 g O = 0.3751 mol O 16 g/mol 0.5556 mol H = 1.5 H 0.3751 mol O = 1 O 0.3702 mol C 1 C 0.3702 mol C 1 C 1.5 1.5 2 3 2The formula is CH O but you cannot have a fraction so, 2(CH O) = C H O Docsity.com 9) When a 15.0 gram sample of an acid is subjected to combustion analysis, 26.76 grams of carbon dioxide and 10.94 grams of water are formed. What is the empirical formula of the compound? 2 226.76 g CO = 0.6082 mol CO ==> 0.6082 mol C 0.6082 mol C x 12 g/mol = 7.2984 g C 44 g/mol 1.2160 mol H x 1 g/mol = 1.2160 g H 8.5144 g Total 2 210.94 g H O = 0.6080 mol H O ==> 1.2160 mol H 15 g - 8.5144 g = 6.4856 g of oxygen 18 g/mol 6.4856 g O = 0.4050 mol O 16 g/mol 0.6082 mol C = 1.5 C 1.2160 mol H = 3 H 0.4050 mol O 1 O 0.4050 mol O 1 C 1.5 3 1.5 3 3 6 2The formula is C H O but you cannot have a fraction so, 2(C H O) = C H O 10) A 15.25 gram sample of an organic acid was combusted in oxygen and produced 34.71 grams of carbon dioxide and 14.20 grams of water. What is the empirical formula of the compound? 2 234.71 g CO = 0.7889 mol CO ==> 0.7889 mol C 0.7889 mol C x 12 g/mol = 9.4668 g C 44 g/mol 1.5778 mol H x 1 g/mol = 1.5778 g H 11.0446 g Total 2 214.20 g H O = 0.7889 mol H O ==> 1.5778 mol H 15.25 g - 11.0446 g = 4.2054 g of oxygen 18 g/mol 4.2054 g O = 0.2628 mol O 16 g/mol 0.7889 mol C = 3 C 1.5778 mol H = 6 H 0.2628 mol O 1 O 0.2628 mol O 1 C 3 6The formula is C H O. Docsity.com
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