The Clausius-Clapeyron Equation, Lecture notes of Chemistry

Download The Clausius-Clapeyron Equation and more Lecture notes Chemistry in PDF only on Docsity! 1. The Clausius-Clapeyron Equation We will utilize the Carnot cycle to derive an important relationship, known as the Clausius- Clapeyron Equation or the first latent heat equation. This equation describes how saturated vapor pressure above a liquid changes with temperature and also how the melting point of a solid changes with pressure. Let the working substance in the cylinder of a Carnot ideal heat engine be a liquid in equilibrium with its saturated vapor and let the initial state of the substance be T− and es, Leg1-2 Let the cylinder be placed on a source of heat at temperature T and let the substance expand isothermally until a unit mass of the liquid evaporates. In this transformation the pressure remains constant at es, and the substance passes from state 1 to 2. If the specific volumes of liquid and vapor at temperature T are αl and αv, respectively, the increase in the volume of the system in passing from 1 to 2 is (αv − αl). Also the heat absorbed from the source is Lv where Lv is the latent heat of vaporization. Leg2-3 The cylinder is now placed on a nonconducting stand and a small adiabatic expansion is carried out from 2 to 3 in which the temperature falls from T to T − dT and the pressure from es − des. Leg3-4 The cylinder is placed on the heat sink at temperature T − dT and an isothermal and isobaric compression is carried out from state 3 to 4 during which vapor is condensed. Leg4-1 We finalize by an adiabatic compression from es − des and T − dT to es and T . All the transformations are reversible, so Q1 T1 = Q2 T2 = Q1 −Q2 T1 − T2 (1) Where Q1 − Q2 is the net heat absorbed by the working substance during one cycle which is also equal to the work done in one cycle. The work done in the cycle is equal to the area enclosed on a p− V diagram. Therefore Q1 −Q2 = (αv − αl)des (2) Also, Q1 = Lv, T1 = T and T1 − T2 = dT , therefore, Lv T = (αv − αl)des dT (3) Which can be re-written as des dT = Lv T (αv − αl) (4) Which is the Clausius-Clapeyron Equation 1 a. Proof of Clausius-Clapeyron using Gibbs Function or Gibbs Free Energy For any two phases (1 and 2) in equilibrium g1 = g2 (5) (6) Proof: In equilibrium T and P of both phases are equal. There is no NET transfer of mass, dg1 = 0 and dg2 = 0. Now, if there is a change of temperature from T by dT and the corresponding change in pres- sure from P by dP and liquid is vaporizing. The Gibbs free energy of the vapor will change by the same amount as that of the liquid. dg1 = dg2 (7) (8) applying the fundamental relations: −(s2 − s1)dT + (α2 − α1)dp = 0 (9) or dp dT = ∆s ∆α (10) Since ds = l T (11) Then dp dT = l T∆α (12) Where l is the latent heat appropriate to the phases present. This is the Clausius-Clapeyron equation and related the equilibrium vapor pressure to the temperature of the heterogeneous sys- tem. It constitutes an equation of state for the heterogeneous system when two phases are present. It is a more generalized form of the equation. lv latent heat of vaporization (liquid-gas) =2.5 × 106Jkg−1 at 0◦C lf latent heat of fusion (solid-liquid) =3.34 × 105Jkg−1 at 0◦C ls latent heat of sublimation (solid-vapor) =2.83 × 106Jkg−1 at 0◦C ls = lf + lv However, the latent heat is a property of the system and depends on the thermodynamic state (generally expressed as a function of temperature) 2