Effect of Temperature and Concentration on Reaction Rate in Chemistry, Schemes and Mind Maps of Law

Download Effect of Temperature and Concentration on Reaction Rate in Chemistry and more Schemes and Mind Maps Law in PDF only on Docsity! Chem 112 Procedure 2 1 THE EFFECT OF TEMPERATURE AND CONCENTRATION ON REACTION RATE INTRODUCTION FACTORS INFLUENCING REACTION RATE: The study of chemical reactions is not complete without a consideration of the rates at which these reactions proceed. We know that some reactions such as those between ions in solution frequently proceed very rapidly, while others proceed so slowly that the rate is not even detectable. The practical importance of these rate considerations is difficult to exaggerate. For example, a metal which is exposed to weather will undergo reactions with oxygen and water which result in corrosion. Among the most important factors influencing the rate of a reaction are: temperature, concentration and catalysis. In addition, for solids the condition of the surface is of great importance. There are two main theories involved in explaining reaction rates. These are the Activated Complex (Transition State) Theory and the Collision Theory. However, in the lecture part of the course, you will also look at the Activated Complex (Transition State) Theory. COLLISION THEORY Consider the simple reaction: A + B Products A and B are atoms, ions, or molecules, in order for A and B to react with each other, they must “collide” together. Since molecules are in rapid and continual motion, molecules of A and Be will collide with one another at frequent intervals. However, not every collision of A and B will result in the formation of products. Before a reaction can occur, the reactants collide with a certain amount of energy, this energy is called “activation energy” or “energy of activation”. This energy comes from the kinetic energy that A and B possess, so that only those collision which occur with sufficient force will be effective in causing reaction. If the concentration of either A or B is doubled, the number of collisions between A and B per time is doubled. If the temperature is raised, the kinetic energies of both A and B are increased so that there are more collisions per second, and a greater fraction of these will lead to chemical reaction. The rate, therefore, generally increases with increasing temperature. The activation energy can be determined by using the Arrhenius Equation: k = Ae-Ea/RT The Arrhenius equation can be re-written as: ln k = - Ea/RT + ln A Where: k = rate constant A = frequency factor Ea = activation energy R = gas constant as: 8.3145 J/mol K T = absolute temperature, K When ln k is plotted against 1/T the slope = -Ea/R and the slope intercept is ln A CATALYSIS A catalyst can be thought of as an agent, which alters the speed of a chemical reaction. This results from a decrease in the amount of activation energy necessary for the reaction. When less activation energy is needed, a larger fraction of the collisions will possess the required energy, and the rate will increase. The manner in which the catalyst lowers the activation energy depends upon the type of catalyst. A catalyst which decreases the speed of a reaction is called an inhibitor. Chem 112 Procedure 2 2 CLOCK REACTION In this experiment, the effect of temperature and concentration on the rate of a chemical reaction will be studied. The reaction chosen, frequently termed the “clock reaction”, is actually a series of consecutive reactions represented by the following equations: BrO3 1- + 6 I1- + 6H+  Br1- + 3I2 + 3 H2O (1) I2 + 2 S2O3 2-  2 I1- + S4O6 2- (2) I2 + Starch  Blue color (3) The iodine that is produced in reaction (1) is immediately used up in reaction (2), so that no appreciable concentration of iodine can build up until all of the Na2S2O3 has been used up. When this occurs, the iodine concentration becomes great enough to change the color of a starch indicator to blue. The appearance of the blue color is thus an indication that all of the Na2S2O3 has been used up. RATE LAW In this experiment, the rate law of the above reaction with be determined. The rate law is: Rate = k [A]x [B]y [C]z The numerical values of x, y , and z will be determined experimentally. x, y, and z are also the order of the reaction with respect to A, B, and C. The sum of the individual orders of the reactant gives the overall order of the reaction. Once, x,y, and z are calculated, the rate constant, k can be calculated. Experiment EQUIPMENT You will be working on this experiment in pairs. Each pair will fill out a slip (names of both students on slip) to check out the following four items form the stockroom: 1 2 mL volumetric pipet 1 3 mL volumetric pipet 3 5 mL volumetric pipets 3 10 mL volumetric pipet 1 pipet helper 1 timer • During the Summer, students should keep all items, storing them in their drawers, until they have finished the experiment. • During the Fall and Spring semesters, students must return all items to the stockroom at the end of the lab period, unless advised otherwise. Chem 112 Procedure 2 5 Answer the following question: 1. Make a plot of Time vs. Temperature (use the average time at each temperature); draw a smooth line through the points. Does the reaction rate increase or decrease with decrease in temperature? Explain, giving two reasons in terms of Collision Theory Calculations/Graph: 1. Using your data and the reaction orders determined in part A, calculate the rate constant, k at for the three temperatures. 2. Graph ln k vs 1/T and then using your graph determine the activation energy. (Hint: The slope = - Ea/R) Tape both graphs to blank pages following Table B. Chem 112 Procedure 2 6 THE EFFECT OF TEMPERATURE AND CONCENTRATION ON REACTION RATE PURPOSE: EQUATIONS: MATERIALS TABLE: SAFETY: PART A- The Effect of Concentration on Reaction Rate: Procedure: Data: Test Tube #1 Test Tube #2 Run # Volume (mL) 0.010 M KI Volume (mL) 0.0010 M Na2S2O3 Volume (mL) water Volume (mL) 0.040 M KBrO3 Volume (mL) 0.10 M HCl Starch Time (secs) Average Time (secs) Average Rate (1/secs) 1 10.00 10.00 10.00 10.00 10.00 5 drops 2 20.00 10.00 0 10.00 10.00 5 drops 3 10.00 10.00 0 20.00 10.00 5 drops 4 10.00 10.00 0 10.00 20.00 5 drops 5 8.00 10.00 12.00 5.00 15.00 5 drops Calculations: 1. a. Summary Table for the Molarity of [I-], [BrO3 -], and [H+] after mixing: Mixtures [I-] [BrO3 -] [H+] 1 2 3 4 5 b. Setups for the calculation of the Molarity of [I-], [BrO3-], and [H+] after mixing. (Show a sample calculation for each of the required calculations) Questions: 1. Using your data, calculate the rate orders with respect to KI, KBrO3, and H+ as well as the overall rate order of the reaction. Note: Use the average times. 2. Calculate the rate constant for the reaction at RT. Chem 112 Procedure 2 7 PART B- The Effect of Temperature on Reaction Rate: Procedure: Data: TABLE B: Temperature vs. Rate Data Approximate Temperature Run # Measured Temperature (°C) Average Temperature (°C) Run Time (seconds) Average Run Time (seconds) Average Rate 1/Time (1/seconds) ~40°C ~ RT* = ____ ~10°C Graphs: Question: 1. Make a plot of Time vs. Temperature (use the average time at each temperature); draw a smooth line through the points. Does the reaction rate increase or decrease with decrease in temperature? Explain, giving two reasons in terms of Collision Theory Calculations/Graph: 1. Using your data and the reaction orders determined in part A, calculate the rate constant, k at for the three temperatures. 2. Graph ln k vs 1/T and then using your graph determine the activation energy (Hint: The slope = - Ea/R) SUMMARY: