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Electric Fields: Point Charges, Dipoles, Line Charges, and Continuous Distributions - Prof, Study notes of Physics

The concepts of electric fields due to point charges, parallel plate capacitors, and the principle of superposition. It also discusses the electric fields of multiple charges, including dipoles and continuous charge distributions. Strategies for calculating electric fields and includes examples and review sections.

Typology: Study notes

Pre 2010

Uploaded on 07/30/2009

koofers-user-s1n
koofers-user-s1n 🇺🇸

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Download Electric Fields: Point Charges, Dipoles, Line Charges, and Continuous Distributions - Prof and more Study notes Physics in PDF only on Docsity! Lecture 18 • Chapter 27 (The Electric Field) due to configuration of (source) charges (today) parallel plate capacitor (uniform ) motion of (other) charges in Ē Ē Ē • good approx. for small charged object, real wire • Coulomb’s law • due to point charge • limiting cases (check + simpler formula): like point charge very far ( size) Electric Field Models Ē Ē ! K = 14!"0 " ! Electric Field of a Continuous Charge Distribution • even if charge is discrete, consider it continuous, describe how it’s distributed (like density, even if atoms • Strategy (based on of point charge and principle of superposition) divide Q into point-like charges find due to convert sum to integral: Ē !Q !Q !Q ! density "dx (x describes shape of !Q) Electric Field of a Line of Charge • Problem • Strategy • Solution...: Infinite line of charge:Eline = limL!" 14!"0 |Q| r ! r2+(L/2)2 = 14!"0 |Q| rL/2 = 1 4!"0 2|#| r Erod = 14!"0 |Q| r ! r2+(L/2)2 Review of Line of charge • due to segment i: • Sum over segments: • Relate to coordinate: • Sum to integral: Ex = Q/L4!"0 ! L/2 !L/2 rdy (r2+y2)3/2 !Q N !"; !y ! dy; !N i ! " L/2 !L/2 Ex = !N i (Ei)x = 1 4!"0 !N i r!Q (r2+y2i ) 3/2 Ex = Q/L4!"0 !N i r!y (r2+y2i ) 3/2 !Q = !!y = (Q/L) !y ! Ēi " x = 1 4!0 !Q r2i cos "i = 1 4!0 r!Q (r2 + y2i ) 3/2
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