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The value oft = 0.1 has been determined by experiments. Ifthe amplitude of steady-state di, Cheat Sheet of Engineering

The value oft = 0.1 has been determined by experiments. Ifthe amplitude of steady-state displacement response x(t) =XsinQot - of the roller is X= 2 cm when excited at the frequency w = 5 rad/see, determine the magnitude To of the applied torque.

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Uploaded on 06/05/2023

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Download The value oft = 0.1 has been determined by experiments. Ifthe amplitude of steady-state di and more Cheat Sheet Engineering in PDF only on Docsity! Solurinws — ME 222 Fall 2017 Practice Problems 1. For the structure below, members ABC and BD are beams. (a) Circle the known displacements and rotations at each point: Point A: @) Point C: Point D: co oO (b) List the unknown reactions at each point: Point A: R KA Ry PointC: Ngne Point D: Ry Ryo Mo D 150kN Y A ' B 45° c x ea > 0.2m 0.2m 0.2m 2. Taking a slice (section cut) between points A and B, the left side of the cut is drawn below. Draw a free body diagram (FBD) of the /eft side of the cut. Be sure to establish a local coordinate system (LCS). Include all internal forces and moments at the cut as well as all external loads. Ry aoa me q Ry Ya 2 Y wes x 4. Find the moment about point C, caused by the force P=16 kN applied at point A. AO? y ron b P=32 kN EN 0.6 un for 2 2.97 + of +2.7k F = fosvt +199 -2.7% a { 0.87 + (8% 42.7% UNIT VECTOR MR GMNITURE F= 3e9t t+307f-~ 28k = ee x & Moser = Vg, % T = J eS 0 2.7 P59 FOB -t2l | Mo/r = C218 +976 Ff 4+ 18,6% ) kam | Mx fy Me 6. In the structure below, the U-shaped structure ABECD is clamped at point D and has a load P=100 Ibs to the left at point A. Member BEC has a rectangular cross section with height 0.4” and width 0.1”. Members AB and CD have identical dimensions. For the loading shown, determine the internal loads (forces and moments) at section E, which is midway between points B and C. si < P=100 Ibs A 6” k 0.4” 24 aaa lov Ibs a SINCE CANTILE VERED, CAN Find (INTER WAL LOAD! W ITKEUT BA LéutATHVG Réaction Ss, FRD:¢UT ATC tou (hs v” Les : & Z us “ f, b Y, Feute: aN av aO -1ma 44,20 |ty= Loo lbs eee ao |4,= 2 CAT Me = 0 Mz +t (c0(béj=oe GCS H
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