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3D Vectors: Components, Magnitude, Direction, Operations, and Unit Vectors, Lecture notes of Mathematics

A comprehensive study on vectors in three-dimensional space, covering topics such as vector components, magnitude and direction, operations on vectors, and unit vectors. It includes examples and solutions for determining the components, magnitude, and direction angles of vectors, as well as operations like sum, negative, difference, and scalar product. The document also explains the concept of unit vectors and provides examples for finding the unit vector in a given direction.

Typology: Lecture notes

2022/2023

Uploaded on 02/13/2024

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Download 3D Vectors: Components, Magnitude, Direction, Operations, and Unit Vectors and more Lecture notes Mathematics in PDF only on Docsity! 2.2 VECTORS IN THREE-DIMENSIONAL SPACE The 3D space The set of all ordered triples of real numbers is called as the three-dimensional number space. 3 R ( ){ }∈= z,y,x|z,y,x R Distance and midpoint points: ( )1111 z,y,xP ( )2222 z,y,xP ( ) ( ) ( )222 zzyyxx −+−+− Distance: or 21PP ( )21 P,Pd 121212 Midpoint:       +++ 222 212121 21 zz , yy , xx M PP Exercise. Determine the distance between the given points and the midpoint of the segment joining them. ( )2342 −− ,,P( )4231 ,,P − Vector in 3D A vector in three-dimensional space is an ordered triple of real numbers . a, bc,b,a and c are called components of the vector. x y z α β γ β γ α MUST!!! Initial point: Terminal point: VECTOR COMPONENTS: ( )ttt z,y,x ( )iii z,y,x ititit zz,yy,xx −−− Magnitude and direction Consider vector . c,b,aA = 222 cbaA ++= If , and are the direction α β γ angles, A a cos =α A b cos =β A c cos =γ 1222 =++ γβα coscoscoswhere Solution (continued) 212 ,,A − 3=A A a cos =α A b cos =β A c cos =γ 3 2 =αcos 3 1− =βcos 3 2 =γcos 3 4 5 4 5 y z initial: terminal: ( )354 ,,− ( )542 ,,− 212 ,,A − γ 1 2 3 4 5 1 2 -1-2-3-4-5 -1 -2 -3 -4 1 2 3 -2 -3 -4 -5 x α β Operations on vectors in 3D 321 b,b,bB=321 a,a,aA= SUM: 332211 ba,ba,baBA +++=+ NEGATIVE: 321 a,a,aA −−−=− DIFFERENCE: 332211 ba,ba,baBA −−−=− SCALAR PRODUCT: 321 ca,ca,cacA= Example. Solution: Consider and . Determine the unit vector in the direction of . 322 ,,A −= 024 ,,B = BA 23 − BA 23 − 02423223 ,,,, −−= 048966 ,,,, −−= 094686 −−−−= ,, 9214 ,,−= Solution (continued) BA 23 − 9214 ,,−= BAU 23 − BA BA 23 23 − − = 9214− ,, ( ) 222 9214 ++− = 184196 9214 ++ − = ,, Solution (continued) BAU 23 − 184196 9214 ++ − = ,, 218 9214 ,,− = 218 9 218 2 218 14 ,, − = 610140950 .,.,.=
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