Stoichiometry Solutions for Neutralization Reactions with Ca(OH)2, H3PO4, Pb(NO3)2, and Na, Exams of Stoichiometry

Download Stoichiometry Solutions for Neutralization Reactions with Ca(OH)2, H3PO4, Pb(NO3)2, and Na and more Exams Stoichiometry in PDF only on Docsity! Chemistry Mr. MacGillivray Solution Stoichiometry Worksheet 1. PROBLEM: What volume of 0.250 M phosphoric acid (H3PO4) is required to neutralize 35.2 ml of 0.338 M calcium hydroxide, Ca(OH)2? 2 3 4 3 4 2___Ca(OH) (aq) + ___H PO (aq) ___Ca (PO ) (s) + ___HOH (l) a. Balance the equation above. b. Fill in the blanks to set up your knowns and unknowns. c. Find the number of moles of calcium hydroxide. Use M=n/V. Show calculations. Units have to cancel, so use liters! Fill in the answer in the “mol” (“n”) box under Ca(OH)2. d. Convert from mol of calcium hydroxide to moles of phosphoric acid. Show your calculations. Fill in the answer above in the “mol” box under phosphoric acid. e. Use M=n/V to find the number of liters of H3PO4. Convert to ml and fill in the answer ! 2. Repeat the above procedure for the following problem: How many ml of a 0.312 M solution of Pb(NO3)2 are needed to react completely with 75.0 ml of 0.500 M NaI? Ca(OH)2 H3PO4 V M n 3 2 2 3___Pb(NO ) + ___ NaI ___ PbI + ___ NaNO ANSWERS Chemistry Mr. MacGillivray Solution Stoichiometry Worksheet 1. PROBLEM: What volume of 0.250 M phosphoric acid (H3PO4) is required to neutralize 35.2 ml of 0.338 M calcium hydroxide, Ca(OH)2? 2 3 4 3 4 23 Ca(OH) (aq) + 2 H PO (aq) Ca (PO ) (s) + 6 HOH (l) a. Balance the equation above. b. Fill in the blanks to set up your knowns and unknowns. c. Find the number of moles of calcium hydroxide. Use M=n/V. Show calculations. Units have to cancel, so use liters! Fill in the answer in the “mol” (“n”) box under Ca(OH)2. d. Convert from mol of calcium hydroxide to moles of phosphoric acid. Show your calculations. Fill in the answer above in the “mol” box under phosphoric acid. e. Use M=n/V to find the number of liters of H3PO4. Convert to ml and fill in the answer ! 35.2 ml V 31.7 ml 0.338 M M 0.250 M 0.0119 moles n 0.00793 moles n = (0.338 )(0.0352 L) = 0.0118976 moles Ca(OH) 2 0.0119 moles Ca(OH) 2 = 0.00793 moles H 3 PO 4 0.0317 liters 31.7 ml